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Sagot :
To identify the slope of the line represented by the equation [tex]\( y = -\frac{2}{3} - 5x \)[/tex], consider the slope-intercept form of a linear equation, which is [tex]\( y = mx + b \)[/tex]. In this format, [tex]\( m \)[/tex] represents the slope, and [tex]\( b \)[/tex] represents the y-intercept.
Given the equation:
[tex]\[ y = -\frac{2}{3} - 5x \][/tex]
we can rewrite it in the format [tex]\( y = mx + b \)[/tex]:
[tex]\[ y = -5x - \frac{2}{3} \][/tex]
Now, it is clear that the coefficient of [tex]\( x \)[/tex] (which is [tex]\( m \)[/tex] in the slope-intercept form) is [tex]\(-5\)[/tex]. Therefore, the slope [tex]\( m \)[/tex] of the line is:
[tex]\[ \boxed{-5} \][/tex]
Given the equation:
[tex]\[ y = -\frac{2}{3} - 5x \][/tex]
we can rewrite it in the format [tex]\( y = mx + b \)[/tex]:
[tex]\[ y = -5x - \frac{2}{3} \][/tex]
Now, it is clear that the coefficient of [tex]\( x \)[/tex] (which is [tex]\( m \)[/tex] in the slope-intercept form) is [tex]\(-5\)[/tex]. Therefore, the slope [tex]\( m \)[/tex] of the line is:
[tex]\[ \boxed{-5} \][/tex]
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