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What is the completely factored form of this polynomial?
[tex]\[ 5x^4 + 20x^3 - 105x^2 \][/tex]

A. [tex]\(5x^3(x-3)(x+7)\)[/tex]
B. [tex]\(5x^2(x-3)(x+7)\)[/tex]
C. [tex]\(5x^3(x+3)(x-7)\)[/tex]
D. [tex]\(5x^2(x+3)(x-7)\)[/tex]


Sagot :

To determine the completely factored form of the polynomial [tex]\(5x^4 + 20x^3 - 105x^2\)[/tex], let's go through the process step-by-step.

1. First, factor out the greatest common factor (GCF) of the polynomial terms.

All terms have [tex]\(x^2\)[/tex] and a common factor of 5:
[tex]\[ 5x^4 + 20x^3 - 105x^2 = 5x^2(x^2 + 4x - 21) \][/tex]

2. Next, we need to factor the quadratic polynomial [tex]\(x^2 + 4x - 21\)[/tex].

We look for two numbers that multiply to [tex]\(-21\)[/tex] (the constant term) and add up to [tex]\(4\)[/tex] (the coefficient of [tex]\(x\)[/tex]):

These numbers are [tex]\(7\)[/tex] and [tex]\(-3\)[/tex], since:
[tex]\[ 7 \times (-3) = -21 \quad \text{and} \quad 7 + (-3) = 4 \][/tex]

So, we can factor [tex]\(x^2 + 4x - 21\)[/tex] as:
[tex]\[ x^2 + 4x - 21 = (x - 3)(x + 7) \][/tex]

3. Putting it all together, we factor the original polynomial completely:

[tex]\[ 5x^4 + 20x^3 - 105x^2 = 5x^2(x^2 + 4x - 21) = 5x^2(x - 3)(x + 7) \][/tex]

Therefore, the completely factored form of the polynomial is:

[tex]\[ 5x^2(x - 3)(x + 7) \][/tex]

This matches with option B.

Hence, the correct answer is:

B. [tex]\(5x^2(x-3)(x+7)\)[/tex]