IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.
Sagot :
To express [tex]\(\log_b \frac{G}{6}\)[/tex] as a difference of logarithms, we will utilize the properties of logarithms.
The logarithm property that we will use is:
[tex]\[ \log_b \left(\frac{M}{N}\right) = \log_b M - \log_b N \][/tex]
This property states that the logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator.
Given the expression [tex]\(\log_b \frac{G}{6}\)[/tex]:
1. Identify the numerator and the denominator in the expression. Here, [tex]\(G\)[/tex] is the numerator and [tex]\(6\)[/tex] is the denominator.
2. Apply the logarithm quotient property.
So, we have:
[tex]\[ \log_b \frac{G}{6} = \log_b G - \log_b 6 \][/tex]
Therefore:
[tex]\[ \log_b \frac{G}{6} = \log_b G - \log_b 6 \][/tex]
Thus, the logarithm [tex]\(\log_b \frac{G}{6}\)[/tex] can be expressed as the difference of [tex]\(\log_b G\)[/tex] and [tex]\(\log_b 6\)[/tex], i.e., [tex]\(\log_b G - \log_b 6\)[/tex].
The logarithm property that we will use is:
[tex]\[ \log_b \left(\frac{M}{N}\right) = \log_b M - \log_b N \][/tex]
This property states that the logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator.
Given the expression [tex]\(\log_b \frac{G}{6}\)[/tex]:
1. Identify the numerator and the denominator in the expression. Here, [tex]\(G\)[/tex] is the numerator and [tex]\(6\)[/tex] is the denominator.
2. Apply the logarithm quotient property.
So, we have:
[tex]\[ \log_b \frac{G}{6} = \log_b G - \log_b 6 \][/tex]
Therefore:
[tex]\[ \log_b \frac{G}{6} = \log_b G - \log_b 6 \][/tex]
Thus, the logarithm [tex]\(\log_b \frac{G}{6}\)[/tex] can be expressed as the difference of [tex]\(\log_b G\)[/tex] and [tex]\(\log_b 6\)[/tex], i.e., [tex]\(\log_b G - \log_b 6\)[/tex].
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.