Join IDNLearn.com today and start getting the answers you've been searching for. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.
Sagot :
Let's analyze the given reaction and each option to determine the correct answer.
The reaction given is:
[tex]\[ \text{CH}_3\text{CO}_2\text{H} \rightleftharpoons \text{H}_3\text{O}^+ + \text{CH}_3\text{CO}_2^- \][/tex]
This is an equilibrium reaction where acetic acid (CH[tex]\(_3\)[/tex]CO[tex]\(_2\)[/tex]H) dissociates in water to form hydronium ions (H[tex]\(_3\)[/tex]O[tex]\(^+\)[/tex]) and acetate ions (CH[tex]\(_3\)[/tex]CO[tex]\(_2^-\)[/tex]).
Understanding Acid and Base Behavior:
1. Acid: A substance that donates a proton (H[tex]\(^+\)[/tex]).
2. Base: A substance that accepts a proton.
In this reaction:
- [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] (acetic acid) donates a proton to water.
- Water (H[tex]\(_2\)[/tex]O) accepts a proton from acetic acid to form [tex]\(\text{H}_3\text{O}^+\)[/tex] (hydronium ion).
Identifying Conjugate Pairs:
- When an acid loses a proton, it forms its conjugate base.
- When a base gains a proton, it forms its conjugate acid.
In this case:
- [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex]---→---[tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] + [tex]\(\text{H}_3\text{O}^+\)[/tex]
- Acetic acid ([tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex]) acts as an acid by donating a proton to water.
- The acetate ion ([tex]\(\text{CH}_3\text{CO}_2^-\)[/tex]) is the conjugate base of acetic acid.
- The hydronium ion ([tex]\(\text{H}_3\text{O}^+\)[/tex]) is the conjugate acid of water.
Evaluating Options:
A) [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is a base, and [tex]\(\text{H}_3\text{O}^+\)[/tex] is its conjugate acid.
- False: [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is an acid, not a base.
B) [tex]\(\text{H}_3\text{O}^+\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is its conjugate base.
- False: The conjugate base of [tex]\(\text{H}_3\text{O}^+\)[/tex] would be water (H[tex]\(_2\)[/tex]O), not [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex].
C) [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is its conjugate base.
- True: [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] donates a proton, making it an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is the resulting conjugate base.
D) [tex]\(\text{H}_3\text{O}^+\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is its conjugate base.
- False: The conjugate base of [tex]\(\text{H}_3\text{O}^+\)[/tex] is water, not [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex].
Therefore, the correct answer is:
C) [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is its conjugate base.
The reaction given is:
[tex]\[ \text{CH}_3\text{CO}_2\text{H} \rightleftharpoons \text{H}_3\text{O}^+ + \text{CH}_3\text{CO}_2^- \][/tex]
This is an equilibrium reaction where acetic acid (CH[tex]\(_3\)[/tex]CO[tex]\(_2\)[/tex]H) dissociates in water to form hydronium ions (H[tex]\(_3\)[/tex]O[tex]\(^+\)[/tex]) and acetate ions (CH[tex]\(_3\)[/tex]CO[tex]\(_2^-\)[/tex]).
Understanding Acid and Base Behavior:
1. Acid: A substance that donates a proton (H[tex]\(^+\)[/tex]).
2. Base: A substance that accepts a proton.
In this reaction:
- [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] (acetic acid) donates a proton to water.
- Water (H[tex]\(_2\)[/tex]O) accepts a proton from acetic acid to form [tex]\(\text{H}_3\text{O}^+\)[/tex] (hydronium ion).
Identifying Conjugate Pairs:
- When an acid loses a proton, it forms its conjugate base.
- When a base gains a proton, it forms its conjugate acid.
In this case:
- [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex]---→---[tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] + [tex]\(\text{H}_3\text{O}^+\)[/tex]
- Acetic acid ([tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex]) acts as an acid by donating a proton to water.
- The acetate ion ([tex]\(\text{CH}_3\text{CO}_2^-\)[/tex]) is the conjugate base of acetic acid.
- The hydronium ion ([tex]\(\text{H}_3\text{O}^+\)[/tex]) is the conjugate acid of water.
Evaluating Options:
A) [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is a base, and [tex]\(\text{H}_3\text{O}^+\)[/tex] is its conjugate acid.
- False: [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is an acid, not a base.
B) [tex]\(\text{H}_3\text{O}^+\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is its conjugate base.
- False: The conjugate base of [tex]\(\text{H}_3\text{O}^+\)[/tex] would be water (H[tex]\(_2\)[/tex]O), not [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex].
C) [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is its conjugate base.
- True: [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] donates a proton, making it an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is the resulting conjugate base.
D) [tex]\(\text{H}_3\text{O}^+\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is its conjugate base.
- False: The conjugate base of [tex]\(\text{H}_3\text{O}^+\)[/tex] is water, not [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex].
Therefore, the correct answer is:
C) [tex]\(\text{CH}_3\text{CO}_2\text{H}\)[/tex] is an acid, and [tex]\(\text{CH}_3\text{CO}_2^-\)[/tex] is its conjugate base.
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.