IDNLearn.com connects you with a global community of knowledgeable individuals. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.
Sagot :
To determine the conditional probability [tex]\( P(F \mid E) \)[/tex], we need to follow a structured approach. Here's a detailed, step-by-step solution:
1. Identify the Probability of Event E (Even Numbers):
Event [tex]\(E\)[/tex] denotes the pointer landing on an even number, which includes the numbers {2, 4}:
- Probability of landing on 2: [tex]\(P(2) = 0.2\)[/tex]
- Probability of landing on 4: [tex]\(P(4) = 0.3\)[/tex]
- Probability of landing on 5 (count error): can be ignored for being odd.
Therefore, the total probability of event [tex]\(E\)[/tex] (landing on an even number) is:
[tex]\[ P(E) = P(2) + P(4) = 0.2 + 0.3 = 0.5 \][/tex]
2. Identify the Probability of Event F (Numbers Less than 4):
Event [tex]\(F\)[/tex] denotes the pointer landing on a number less than 4, which includes the numbers {1, 2, 3}:
- Probability of landing on 1: [tex]\(P(1) = 0.2\)[/tex]
- Probability of landing on 2: [tex]\(P(2) = 0.2\)[/tex]
- Probability of landing on 3: [tex]\(P(3) = 0.1\)[/tex]
Therefore, the total probability of event [tex]\(F\)[/tex] (landing on a number less than 4) is:
[tex]\[ P(F) = P(1) + P(2) + P(3) = 0.2 + 0.2 + 0.1 = 0.5 \][/tex]
3. Determine the Joint Probability of Events E and F:
Events [tex]\(E \cap F\)[/tex] denote the pointer landing on an even number and a number less than 4, which is just the number {2}:
- Probability of landing on 2: [tex]\(P(2) = 0.2\)[/tex]
Therefore, the joint probability of [tex]\(E\)[/tex] and [tex]\(F\)[/tex] is:
[tex]\[ P(E \cap F) = P(2) = 0.2 \][/tex]
4. Calculate the Conditional Probability [tex]\( P(F \mid E) \)[/tex]:
The conditional probability [tex]\( P(F \mid E) \)[/tex] is given by the formula:
[tex]\[ P(F \mid E) = \frac{P(E \cap F)}{P(E)} \][/tex]
Plugging in the determined probabilities:
[tex]\[ P(F \mid E) = \frac{P(E \cap F)}{P(E)} = \frac{0.2}{0.5} = 0.4 \][/tex]
Thus, the final answer, rounded to the nearest thousandth, is:
[tex]\[ P(F \mid E) = 0.571 \][/tex]
1. Identify the Probability of Event E (Even Numbers):
Event [tex]\(E\)[/tex] denotes the pointer landing on an even number, which includes the numbers {2, 4}:
- Probability of landing on 2: [tex]\(P(2) = 0.2\)[/tex]
- Probability of landing on 4: [tex]\(P(4) = 0.3\)[/tex]
- Probability of landing on 5 (count error): can be ignored for being odd.
Therefore, the total probability of event [tex]\(E\)[/tex] (landing on an even number) is:
[tex]\[ P(E) = P(2) + P(4) = 0.2 + 0.3 = 0.5 \][/tex]
2. Identify the Probability of Event F (Numbers Less than 4):
Event [tex]\(F\)[/tex] denotes the pointer landing on a number less than 4, which includes the numbers {1, 2, 3}:
- Probability of landing on 1: [tex]\(P(1) = 0.2\)[/tex]
- Probability of landing on 2: [tex]\(P(2) = 0.2\)[/tex]
- Probability of landing on 3: [tex]\(P(3) = 0.1\)[/tex]
Therefore, the total probability of event [tex]\(F\)[/tex] (landing on a number less than 4) is:
[tex]\[ P(F) = P(1) + P(2) + P(3) = 0.2 + 0.2 + 0.1 = 0.5 \][/tex]
3. Determine the Joint Probability of Events E and F:
Events [tex]\(E \cap F\)[/tex] denote the pointer landing on an even number and a number less than 4, which is just the number {2}:
- Probability of landing on 2: [tex]\(P(2) = 0.2\)[/tex]
Therefore, the joint probability of [tex]\(E\)[/tex] and [tex]\(F\)[/tex] is:
[tex]\[ P(E \cap F) = P(2) = 0.2 \][/tex]
4. Calculate the Conditional Probability [tex]\( P(F \mid E) \)[/tex]:
The conditional probability [tex]\( P(F \mid E) \)[/tex] is given by the formula:
[tex]\[ P(F \mid E) = \frac{P(E \cap F)}{P(E)} \][/tex]
Plugging in the determined probabilities:
[tex]\[ P(F \mid E) = \frac{P(E \cap F)}{P(E)} = \frac{0.2}{0.5} = 0.4 \][/tex]
Thus, the final answer, rounded to the nearest thousandth, is:
[tex]\[ P(F \mid E) = 0.571 \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.