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### 7. Given:
- [tex]\( AC = -3 + 6x \)[/tex]
- [tex]\( AB = 3x - 3 \)[/tex]
- [tex]\( BC = 9 \)[/tex]
Since A, B, and C are collinear and B is between A and C, we have:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (3x - 3) + 9 = -3 + 6x \][/tex]
Solving this equation for [tex]\( x \)[/tex]:
[tex]\[ 3x - 3 + 9 = -3 + 6x \][/tex]
[tex]\[ 3x + 6 = -3 + 6x \][/tex]
[tex]\[ 6 + 3 = 3x \][/tex]
[tex]\[ 9 = 3x \][/tex]
[tex]\[ x = 3 \][/tex]
### 8. Given:
- [tex]\( AB = 2x + 22 \)[/tex]
- [tex]\( BC = 3 \)[/tex]
- [tex]\( AC = x + 17 \)[/tex]
Again, since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (2x + 22) + 3 = x + 17 \][/tex]
[tex]\[ 2x + 25 = x + 17 \][/tex]
[tex]\[ 2x - x = 17 - 25 \][/tex]
[tex]\[ x = -8 \][/tex]
### 9. Given:
- [tex]\( AB = x + 12 \)[/tex]
- [tex]\( BC = x + 12 \)[/tex]
- [tex]\( AC = 14 \)[/tex]
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (x + 12) + (x + 12) = 14 \][/tex]
[tex]\[ 2x + 24 = 14 \][/tex]
[tex]\[ 2x = 14 - 24 \][/tex]
[tex]\[ 2x = -10 \][/tex]
[tex]\[ x = -5 \][/tex]
### 10. Given:
- [tex]\( AC = 22 \)[/tex]
- [tex]\( AB = x + 22 \)[/tex]
- [tex]\( BC = x + 20 \)[/tex]
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (x + 22) + (x + 20) = 22 \][/tex]
[tex]\[ 2x + 42 = 22 \][/tex]
[tex]\[ 2x = 22 - 42 \][/tex]
[tex]\[ 2x = -20 \][/tex]
[tex]\[ x = -10 \][/tex]
### 11. Given:
- [tex]\( AC = 3x - 5 \)[/tex]
- [tex]\( BC = 10 \)[/tex]
- [tex]\( AB = -7 + 2x \)[/tex]
We are asked to find [tex]\( \dot{A B} \)[/tex], which means solving for [tex]\( x \)[/tex] first:
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (-7 + 2x) + 10 = 3x - 5 \][/tex]
[tex]\[ 2x + 3 = 3x - 5 \][/tex]
[tex]\[ 3 + 5 = 3x - 2x \][/tex]
[tex]\[ 8 = x \][/tex]
Thus,
[tex]\[ A \dot{B} = 8 \][/tex]
### 12. Given:
- [tex]\( AB = 9 \)[/tex]
- [tex]\( AC = 5x - 1 \)[/tex]
- [tex]\( BC = 2x + 2 \)[/tex]
We are asked to find [tex]\( \dot{B C} \)[/tex], which means solving for [tex]\( x \)[/tex] first:
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ 9 + (2x + 2) = 5x - 1 \][/tex]
[tex]\[ 11 + 2x = 5x - 1 \][/tex]
[tex]\[ 11 + 1 = 5x - 2x \][/tex]
[tex]\[ 12 = 3x \][/tex]
[tex]\[ x = 4 \][/tex]
Thus,
[tex]\[ B \dot{C} = 4 \][/tex]
So, the solutions for each part are:
[tex]\[ \text{7) } x = 3 \][/tex]
[tex]\[ \text{8) } x = -8 \][/tex]
[tex]\[ \text{9) } x = -5 \][/tex]
[tex]\[ \text{10) } x = -10 \][/tex]
[tex]\[ \text{11) } x = 8 \][/tex]
[tex]\[ \text{12) } x = 4 \][/tex]
### 7. Given:
- [tex]\( AC = -3 + 6x \)[/tex]
- [tex]\( AB = 3x - 3 \)[/tex]
- [tex]\( BC = 9 \)[/tex]
Since A, B, and C are collinear and B is between A and C, we have:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (3x - 3) + 9 = -3 + 6x \][/tex]
Solving this equation for [tex]\( x \)[/tex]:
[tex]\[ 3x - 3 + 9 = -3 + 6x \][/tex]
[tex]\[ 3x + 6 = -3 + 6x \][/tex]
[tex]\[ 6 + 3 = 3x \][/tex]
[tex]\[ 9 = 3x \][/tex]
[tex]\[ x = 3 \][/tex]
### 8. Given:
- [tex]\( AB = 2x + 22 \)[/tex]
- [tex]\( BC = 3 \)[/tex]
- [tex]\( AC = x + 17 \)[/tex]
Again, since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (2x + 22) + 3 = x + 17 \][/tex]
[tex]\[ 2x + 25 = x + 17 \][/tex]
[tex]\[ 2x - x = 17 - 25 \][/tex]
[tex]\[ x = -8 \][/tex]
### 9. Given:
- [tex]\( AB = x + 12 \)[/tex]
- [tex]\( BC = x + 12 \)[/tex]
- [tex]\( AC = 14 \)[/tex]
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (x + 12) + (x + 12) = 14 \][/tex]
[tex]\[ 2x + 24 = 14 \][/tex]
[tex]\[ 2x = 14 - 24 \][/tex]
[tex]\[ 2x = -10 \][/tex]
[tex]\[ x = -5 \][/tex]
### 10. Given:
- [tex]\( AC = 22 \)[/tex]
- [tex]\( AB = x + 22 \)[/tex]
- [tex]\( BC = x + 20 \)[/tex]
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (x + 22) + (x + 20) = 22 \][/tex]
[tex]\[ 2x + 42 = 22 \][/tex]
[tex]\[ 2x = 22 - 42 \][/tex]
[tex]\[ 2x = -20 \][/tex]
[tex]\[ x = -10 \][/tex]
### 11. Given:
- [tex]\( AC = 3x - 5 \)[/tex]
- [tex]\( BC = 10 \)[/tex]
- [tex]\( AB = -7 + 2x \)[/tex]
We are asked to find [tex]\( \dot{A B} \)[/tex], which means solving for [tex]\( x \)[/tex] first:
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ (-7 + 2x) + 10 = 3x - 5 \][/tex]
[tex]\[ 2x + 3 = 3x - 5 \][/tex]
[tex]\[ 3 + 5 = 3x - 2x \][/tex]
[tex]\[ 8 = x \][/tex]
Thus,
[tex]\[ A \dot{B} = 8 \][/tex]
### 12. Given:
- [tex]\( AB = 9 \)[/tex]
- [tex]\( AC = 5x - 1 \)[/tex]
- [tex]\( BC = 2x + 2 \)[/tex]
We are asked to find [tex]\( \dot{B C} \)[/tex], which means solving for [tex]\( x \)[/tex] first:
Since A, B, and C are collinear and B is between A and C:
[tex]\[ AB + BC = AC \][/tex]
Substituting the given values:
[tex]\[ 9 + (2x + 2) = 5x - 1 \][/tex]
[tex]\[ 11 + 2x = 5x - 1 \][/tex]
[tex]\[ 11 + 1 = 5x - 2x \][/tex]
[tex]\[ 12 = 3x \][/tex]
[tex]\[ x = 4 \][/tex]
Thus,
[tex]\[ B \dot{C} = 4 \][/tex]
So, the solutions for each part are:
[tex]\[ \text{7) } x = 3 \][/tex]
[tex]\[ \text{8) } x = -8 \][/tex]
[tex]\[ \text{9) } x = -5 \][/tex]
[tex]\[ \text{10) } x = -10 \][/tex]
[tex]\[ \text{11) } x = 8 \][/tex]
[tex]\[ \text{12) } x = 4 \][/tex]
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