Discover a wealth of information and get your questions answered on IDNLearn.com. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.
Sagot :
Let's tackle this question step-by-step.
### (a) Write down the matrices of [tex]\( P, Q \)[/tex], and [tex]\( R \)[/tex]
First, we need to translate the given transformations into matrix form.
1. Transformation [tex]\( P \)[/tex]
[tex]\[ P: (x, y) \rightarrow (-4x - y, 2x) \][/tex]
To represent this transformation as a matrix, we can write:
[tex]\[ \begin{pmatrix} -4x - y \\ 2x \end{pmatrix} \][/tex]
This corresponds to the matrix:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
2. Transformation [tex]\( Q \)[/tex]
[tex]\[ Q: (x, y) \rightarrow (y, 6x - 9y) \][/tex]
To represent this transformation as a matrix, we can write:
[tex]\[ \begin{pmatrix} y \\ 6x - 9y \end{pmatrix} \][/tex]
This corresponds to the matrix:
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
3. Transformation [tex]\( R \)[/tex]
[tex]\[ R: (x, y) \rightarrow (x - 2y, 3x + 5y) \][/tex]
To represent this transformation as a matrix, we can write:
[tex]\[ \begin{pmatrix} x - 2y \\ 3x + 5y \end{pmatrix} \][/tex]
This corresponds to the matrix:
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
The matrices for [tex]\( P, Q \)[/tex], and [tex]\( R \)[/tex] are:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
### (b) Calculate the result matrices
The result obtained for the matrices from the transformations is:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
Hence, the matrices for these transformations are correctly identified and look like this:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
### (a) Write down the matrices of [tex]\( P, Q \)[/tex], and [tex]\( R \)[/tex]
First, we need to translate the given transformations into matrix form.
1. Transformation [tex]\( P \)[/tex]
[tex]\[ P: (x, y) \rightarrow (-4x - y, 2x) \][/tex]
To represent this transformation as a matrix, we can write:
[tex]\[ \begin{pmatrix} -4x - y \\ 2x \end{pmatrix} \][/tex]
This corresponds to the matrix:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
2. Transformation [tex]\( Q \)[/tex]
[tex]\[ Q: (x, y) \rightarrow (y, 6x - 9y) \][/tex]
To represent this transformation as a matrix, we can write:
[tex]\[ \begin{pmatrix} y \\ 6x - 9y \end{pmatrix} \][/tex]
This corresponds to the matrix:
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
3. Transformation [tex]\( R \)[/tex]
[tex]\[ R: (x, y) \rightarrow (x - 2y, 3x + 5y) \][/tex]
To represent this transformation as a matrix, we can write:
[tex]\[ \begin{pmatrix} x - 2y \\ 3x + 5y \end{pmatrix} \][/tex]
This corresponds to the matrix:
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
The matrices for [tex]\( P, Q \)[/tex], and [tex]\( R \)[/tex] are:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
### (b) Calculate the result matrices
The result obtained for the matrices from the transformations is:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
Hence, the matrices for these transformations are correctly identified and look like this:
[tex]\[ P = \begin{pmatrix} -4 & -1 \\ 2 & 0 \end{pmatrix} \][/tex]
[tex]\[ Q = \begin{pmatrix} 0 & 1 \\ 6 & -9 \end{pmatrix} \][/tex]
[tex]\[ R = \begin{pmatrix} 1 & -2 \\ 3 & 5 \end{pmatrix} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.