Experience the convenience of getting your questions answered at IDNLearn.com. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.
Sagot :
To divide the polynomial [tex]\( x^3 - 2x^2 + 16 \)[/tex] by [tex]\( x + 2 \)[/tex], we can use polynomial long division. Let me guide you through the long division process step by step.
1. Setup the Division:
Write the dividend [tex]\( x^3 - 2x^2 + 16 \)[/tex] under the long division symbol and the divisor [tex]\( x + 2 \)[/tex] outside.
```
x^2 - 4x + 8
___________________________________________________
x + 2 | x^3 - 2x^2 + 0x + 16
```
2. First Division:
- Divide the leading term of the dividend [tex]\( x^3 \)[/tex] by the leading term of the divisor [tex]\( x \)[/tex], which gives [tex]\( x^2 \)[/tex].
- Multiply the entire divisor [tex]\( x + 2 \)[/tex] by [tex]\( x^2 \)[/tex] and subtract from the original polynomial.
[tex]\[ x^3 - 2x^2 + 0x + 16 - (x^3 + 2x^2) = -4x^2 + 0x + 16 ``` 3. Second Division: - Divide the new dividend's leading term \( -4x^2 \) by the leading term of the divisor \( x \), which gives \( -4x \). - Multiply the entire divisor \( x + 2 \) by \( -4x \) and subtract from the current result. \[ -4x^2 + 0x + 16 - (-4x^2 - 8x) = 8x + 16 ``` 4. Third Division: - Divide the new dividend's leading term \( 8x \) by the leading term of the divisor \( x \), which gives \( 8 \). - Multiply the entire divisor \( x + 2 \) by \( 8 \) and subtract from the current result. \[ 8x + 16 - (8x + 16) = 0 ``` After performing these steps, we arrive at: Quotient: \( x^2 - 4x + 8 \) \ Remainder: \( 0 \) Therefore, the result of dividing \( x^3 - 2x^2 + 16 \) by \( x + 2 \) is: \[ \boxed{(x^2 - 4x + 8, 0)} \][/tex]
1. Setup the Division:
Write the dividend [tex]\( x^3 - 2x^2 + 16 \)[/tex] under the long division symbol and the divisor [tex]\( x + 2 \)[/tex] outside.
```
x^2 - 4x + 8
___________________________________________________
x + 2 | x^3 - 2x^2 + 0x + 16
```
2. First Division:
- Divide the leading term of the dividend [tex]\( x^3 \)[/tex] by the leading term of the divisor [tex]\( x \)[/tex], which gives [tex]\( x^2 \)[/tex].
- Multiply the entire divisor [tex]\( x + 2 \)[/tex] by [tex]\( x^2 \)[/tex] and subtract from the original polynomial.
[tex]\[ x^3 - 2x^2 + 0x + 16 - (x^3 + 2x^2) = -4x^2 + 0x + 16 ``` 3. Second Division: - Divide the new dividend's leading term \( -4x^2 \) by the leading term of the divisor \( x \), which gives \( -4x \). - Multiply the entire divisor \( x + 2 \) by \( -4x \) and subtract from the current result. \[ -4x^2 + 0x + 16 - (-4x^2 - 8x) = 8x + 16 ``` 4. Third Division: - Divide the new dividend's leading term \( 8x \) by the leading term of the divisor \( x \), which gives \( 8 \). - Multiply the entire divisor \( x + 2 \) by \( 8 \) and subtract from the current result. \[ 8x + 16 - (8x + 16) = 0 ``` After performing these steps, we arrive at: Quotient: \( x^2 - 4x + 8 \) \ Remainder: \( 0 \) Therefore, the result of dividing \( x^3 - 2x^2 + 16 \) by \( x + 2 \) is: \[ \boxed{(x^2 - 4x + 8, 0)} \][/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.