IDNLearn.com: Your trusted source for finding accurate answers. Our platform is designed to provide trustworthy and thorough answers to any questions you may have.
Sagot :
Answer:
28.57
Explanation:
To find the distance the car travels before it stops, we can use the equations of motion for uniformly decelerated motion.
Given:
- Initial velocity, \( u = 20 \) m/s (since the car is slowing down, we take it as positive)
- Acceleration (deceleration), \( a = -7 \) m/s\(^2\) (negative because it's deceleration)
- Final velocity, \( v = 0 \) m/s (since the car stops)
We need to find the distance \( s \).
The equation relating initial velocity, final velocity, acceleration, and distance is:
\[ v^2 = u^2 + 2as \]
Substitute the given values:
\[ 0 = (20)^2 + 2 \cdot (-7) \cdot s \]
Simplify and solve for \( s \):
\[ 0 = 400 - 14s \]
\[ 14s = 400 \]
\[ s = \frac{400}{14} \]
\[ s = 28.57 \text{ meters} \]
So, the car travels approximately \( 28.57 \) meters before it stops.
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.
