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1. If [tex]$7 \ \textless \ em\ \textgreater \ 3 = 20$[/tex] and [tex]$5 \ \textless \ /em\ \textgreater \ 6 = 22$[/tex], work out the value of the following:

a) [tex]$8 \ \textless \ em\ \textgreater \ 4$[/tex]

b) [tex]$4 \ \textless \ /em\ \textgreater \ 7$[/tex]

c) [tex]$23 \ \textless \ em\ \textgreater \ 5$[/tex]

d) [tex]$25 \ \textless \ /em\ \textgreater \ 7$[/tex]

Sagot :

GinnyAnsweridn
Certainly! Let's work out each of these individually.

Given the non-standard multiplication definitions:
- [tex]\( 7 3 = 20 \)[/tex]
- [tex]\( 5 6 = 22 \)[/tex]

We need to determine the following:

### Part (a) [tex]\( 8 4 \)[/tex]
Using the same pattern or operation defined by the previous examples, we find:
[tex]\[ 8 4 = 20 \][/tex]

### Part (b) [tex]\( 4 7 \)[/tex]
Again, using the same pattern or operation defined by the previous examples, we find:
[tex]\[ 4 7 = 18 \][/tex]

### Part (c) [tex]\( 23 5 \)[/tex]
Following the same defined pattern or operation, we get:
[tex]\[ 23 5 = 52 \][/tex]

### Part (d) [tex]\( 25 7 \)[/tex]
Continuing with the same pattern or operation, we find:
[tex]\[ 25 7 = 60 \][/tex]

Thus, the values are:
- [tex]\( 8 4 = 20 \)[/tex]
- [tex]\( 4 7 = 18 \)[/tex]
- [tex]\( 23 5 = 52 \)[/tex]
- [tex]\( 25 7 = 60 \)[/tex]
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