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Breeding Lineages (BBEE [tex]$\times$[/tex] bbee)

For each offspring genotype in the Punnett square you just completed, determine the phenotype. In other words, what is the predicted fur color and eye color of the offspring? Using your Punnett square from the last step, fill in the predicted fraction for each phenotype in the data table below.

\begin{tabular}{|l|c|c|c|c|c|}
\cline{2-5}
& \begin{tabular}{c}
Black Fur and \\
Black Eyes
\end{tabular}
& \begin{tabular}{c}
Black Fur and \\
Red Eyes
\end{tabular}
& \begin{tabular}{c}
White Fur and \\
Black Eyes
\end{tabular}
& \begin{tabular}{c}
White Fur and \\
Red Eyes
\end{tabular}
\\
\hline
Predicted Fraction & [tex]$\square$[/tex] & [tex]$\square$[/tex] & [tex]$\square$[/tex] & [tex]$\square$[/tex] \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Let's analyze the genetic cross step-by-step to determine the phenotypes and their respective fractions for the offspring.

1. Parental Genotypes and Traits:
- The first parent has the genotype BBEE. This parent has:
- Black Fur (dominant allele B)
- Black Eyes (dominant allele E)
- The second parent has the genotype bbee. This parent has:
- White Fur (recessive allele b)
- Red Eyes (recessive allele e)

2. Possible Gametes:
- BBEE can only produce gametes with BE.
- bbee can only produce gametes with be.

3. Crossing the Gametes:
- When BE from the first parent is crossed with be from the second parent, the genotype of the offspring will be:
- BbEe

4. Determining the Phenotype for BbEe:
- B (Black Fur) is dominant over b (White Fur).
- E (Black Eyes) is dominant over e (Red Eyes).
- Therefore, the offspring with the genotype BbEe will exhibit:
- Black Fur (due to the presence of at least one dominant B)
- Black Eyes (due to the presence of at least one dominant E)

5. Predicted Fraction for Each Phenotype:
- As all offspring have the same genotype BbEe, they all have the same phenotype, which is Black Fur and Black Eyes.

Thus, the predicted fractions for each phenotype are:

| Phenotype | Predicted Fraction |
|----------------------------|--------------------|
| Black Fur and Black Eyes | 1.0 |
| Black Fur and Red Eyes | 0.0 |
| White Fur and Black Eyes | 0.0 |
| White Fur and Red Eyes | 0.0 |

Now, filling in the data table:

[tex]\[ \begin{tabular}{|l|c|c|c|c|} \cline { 2 - 5 } & \begin{tabular}{c} Black Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} Black Fur and \\ Red Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Black Eyes \end{tabular} & \begin{tabular}{c} White Fur and \\ Red Eyes \end{tabular} \\ \hline Predicted Fraction & 1.0 & 0.0 & 0.0 & 0.0 \\ \hline \end{tabular} \][/tex]

So, the offspring will all have Black Fur and Black Eyes with a fraction of 1.0, and the other phenotypes will have a fraction of 0.0.
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