To determine the phenotypes from the Punnett square, we need to first understand the genetic traits controlling fur and eye color. Let’s assume we are dealing with two traits:
1. Fur color, where black fur (B) is dominant over white fur (b).
2. Eye color, where black eyes (E) are dominant over red eyes (e).
Given this pairing:
- Black fur, black eyes: BBEE, BbEE, BBEe, BbEe
- Black fur, red eyes: BBee, Bbee
- White fur, black eyes: bbEE, bbEe
- White fur, red eyes: bbee
Let’s say the following genotypes were derived from a completed Punnett square. To fill in the table with the corresponding predicted fractions (i.e., the number of times each phenotype appears out of total 16 combinations):
1. Black Fur and Black Eyes:
- Possible Genotypes: BBEE, BbEE, BBEe, BbEe
- Count: Suppose these genotype combinations appear 9 times.
2. Black Fur and Red Eyes:
- Possible Genotypes: BBee, Bbee
- Count: Suppose these genotype combinations appear 3 times.
3. White Fur and Black Eyes:
- Possible Genotypes: bbEE, bbEe
- Count: Suppose these genotype combinations appear 3 times.
4. White Fur and Red Eyes:
- Possible Genotype: bbee
- Count: Suppose this genotype combination appears 1 time.
Now, let's fill in the data table with the predicted fraction for each phenotype:
\begin{tabular}{|l|c|c|c|c|c|}
\hline
\multicolumn{1}{c|}{\begin{tabular}{c}
Black Fur and \\
Black Eyes
\end{tabular}} & \begin{tabular}{c}
Black Fur and \\
Red Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Black Eyes
\end{tabular} & \begin{tabular}{c}
White Fur and \\
Red Eyes
\end{tabular} & \\
\hline
Predicted Fraction & [tex]\(9 / 16\)[/tex] & [tex]\(3 / 16\)[/tex] & [tex]\(3 / 16\)[/tex] & [tex]\(1 / 16\)[/tex] & DONE IV \\
\hline
\end{tabular}
