To determine which metal the meteorite most likely matches, we need to calculate the density of the meteorite and compare it to the densities given for aluminum, iron, and lead.
### Step-by-Step Solution:
1. Calculate the Density of the Meteorite:
The formula to calculate density is:
[tex]\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\][/tex]
Given:
- Mass of the meteorite, [tex]\( m = 370 \, \text{g} \)[/tex]
- Volume of the meteorite, [tex]\( V = 50 \, \text{cm}^3 \)[/tex]
Substitute the given values into the density formula:
[tex]\[
\text{Density of meteorite} = \frac{370\, \text{g}}{50\, \text{cm}^3} = 7.4 \, \text{g/cm}^3
\][/tex]
2. Compare the Calculated Density to Given Densities:
- Aluminum: [tex]\( 2.64 \, \text{g/cm}^3 \)[/tex]
- Iron: [tex]\( 7.50 \, \text{g/cm}^3 \)[/tex]
- Lead: [tex]\( 11.34 \, \text{g/cm}^3 \)[/tex]
The density we calculated for the meteorite is [tex]\( 7.4 \, \text{g/cm}^3 \)[/tex].
3. Assess the Match:
- The density of the meteorite ([tex]\( 7.4 \, \text{g/cm}^3 \)[/tex]) is not equal to the density of aluminum ([tex]\(2.64 \, \text{g/cm}^3 \)[/tex]).
- It is also not equal to the density of iron ([tex]\(7.50 \, \text{g/cm}^3 \)[/tex]).
- Similarly, it does not match the density of lead ([tex]\(11.34 \, \text{g/cm}^3 \)[/tex]).
- Additionally, the density of the meteorite ([tex]\(7.4 \, \text{g/cm}^3 \)[/tex]) is greater than [tex]\(1.0 \, \text{g/cm}^3 \)[/tex], so it does not correspond to the option "none of these (density is less than 1.0)".
Since the meteorite's density ([tex]\(7.4 \, \text{g/cm}^3 \)[/tex]) does not exactly match any of the provided metal densities, the composition of the meteorite is most likely:
[tex]\[
\textbf{unknown}
\][/tex]
