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Solve the following absolute value inequality:

[tex]\[ \frac{|x+15|}{5} \leq 26 \][/tex]

What is the positive absolute value for [tex]\( x \)[/tex] ?

[tex]\[
\begin{array}{l}
x \leq \\
x \geq
\end{array}
\][/tex]


Sagot :

Let's solve the given absolute value inequality step by step:

Given:
[tex]\[ \frac{|x+15|}{5} \leq 26 \][/tex]

### Step 1: Clear the fraction

Multiply both sides of the inequality by 5 to eliminate the fraction:
[tex]\[ |x + 15| \leq 130 \][/tex]

### Step 2: Break down the absolute value inequality

The inequality [tex]\( |x + 15| \leq 130 \)[/tex] means that the expression inside the absolute value, [tex]\(x + 15\)[/tex], lies between [tex]\(-130\)[/tex] and [tex]\(130\)[/tex]. This can be written as two separate inequalities:
[tex]\[ -130 \leq x + 15 \leq 130 \][/tex]

### Step 3: Solve each inequality separately

First, solve the inequality on the left:
[tex]\[ -130 \leq x + 15 \][/tex]

Subtract 15 from both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ -130 - 15 \leq x \][/tex]
[tex]\[ -145 \leq x \][/tex]

Second, solve the inequality on the right:
[tex]\[ x + 15 \leq 130 \][/tex]

Subtract 15 from both sides to isolate [tex]\(x\)[/tex]:
[tex]\[ x \leq 130 - 15 \][/tex]
[tex]\[ x \leq 115 \][/tex]

### Conclusion

Combining the two inequalities, we have:
[tex]\[ -145 \leq x \leq 115 \][/tex]

### Positive Absolute Value

We need the positive absolute value for [tex]\(x\)[/tex]. Hence, we look at the upper bound of this range:
[tex]\[ x \leq 115 \][/tex]

Thus, the positive absolute value for [tex]\(x\)[/tex] is:
[tex]\[ 115 \][/tex]