Connect with knowledgeable individuals and find the best answers at IDNLearn.com. Our experts provide timely and precise responses to help you understand and solve any issue you face.

Considering the setup from the previous problem, calculate the number of moles of salt in 6.37 grams. The molecular weight of table salt, NaCl, is [tex]58.5 \, g/mol[/tex]. Type in your answer below using the correct number of significant figures.

[tex]6.37 \, g \, \text{NaCl} =[/tex]
[tex]\boxed{}[/tex]


Sagot :

To determine the number of moles of salt (NaCl) in 6.37 grams, follow these steps:

### Step 1: Understand the Given Data
- The weight of NaCl is [tex]\( 6.37 \)[/tex] grams.
- The molecular weight (molar mass) of NaCl is [tex]\( 58.5 \)[/tex] grams per mole.

### Step 2: Use the Formula to Calculate Moles
The formula to calculate the number of moles of a substance is given by:

[tex]\[ \text{Number of moles} = \frac{\text{Mass of the substance}}{\text{Molar mass of the substance}} \][/tex]

### Step 3: Substitute the Given Values into the Formula
Let's plug in the values:
- Mass of NaCl: [tex]\( 6.37 \)[/tex] grams
- Molar mass of NaCl: [tex]\( 58.5 \)[/tex] grams per mole

[tex]\[ \text{Number of moles of NaCl} = \frac{6.37 \text{ grams}}{58.5 \text{ grams per mole}} \][/tex]

### Step 4: Perform the Division
[tex]\[ \text{Number of moles of NaCl} = \frac{6.37}{58.5} \][/tex]

### Step 5: Round the Answer to the Correct Number of Significant Figures
The number of significant figures in the given data (6.37 grams) is 3. Therefore, the answer should also be reported to 3 significant figures:

[tex]\[ \text{Number of moles of NaCl} \approx 0.109 \][/tex]

### Final Answer
[tex]\( 6.37 \text{ grams of NaCl} = 0.109 \text{ moles} \)[/tex]

The number of moles of salt in 6.37 grams of NaCl is therefore [tex]\( \boxed{0.109} \)[/tex].
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.