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To find out how many milliliters of hydrogen are in a 55 ml seawater sample, we need to use the percentage provided for hydrogen in the seawater composition. Here's a detailed, step-by-step solution:
1. Identify the given data:
- The volume of the seawater sample: [tex]\( 55 \)[/tex] ml
- The percentage of hydrogen in seawater: [tex]\( 10.824\% \)[/tex]
2. Understand what needs to be calculated:
- We need to determine the volume of hydrogen in the 55 ml sample.
3. Set up the equation:
- Since the percentage represents the proportion of the sample that is hydrogen, we can set up the equation as:
[tex]\[ \text{Hydrogen volume} = \left( \frac{\text{Hydrogen percent}}{100} \right) \times \text{Sample volume} \][/tex]
4. Substitute the given values into the equation:
[tex]\[ \text{Hydrogen volume} = \left( \frac{10.824}{100} \right) \times 55 \][/tex]
5. Perform the calculation:
[tex]\[ \text{Hydrogen volume} = 0.10824 \times 55 = 5.9532 \][/tex]
6. Round the result to two decimal places:
- The volume of hydrogen in the sample is [tex]\( 5.95 \)[/tex] ml.
Therefore, there are [tex]\( \boxed{5.95} \)[/tex] ml of hydrogen in the sample.
1. Identify the given data:
- The volume of the seawater sample: [tex]\( 55 \)[/tex] ml
- The percentage of hydrogen in seawater: [tex]\( 10.824\% \)[/tex]
2. Understand what needs to be calculated:
- We need to determine the volume of hydrogen in the 55 ml sample.
3. Set up the equation:
- Since the percentage represents the proportion of the sample that is hydrogen, we can set up the equation as:
[tex]\[ \text{Hydrogen volume} = \left( \frac{\text{Hydrogen percent}}{100} \right) \times \text{Sample volume} \][/tex]
4. Substitute the given values into the equation:
[tex]\[ \text{Hydrogen volume} = \left( \frac{10.824}{100} \right) \times 55 \][/tex]
5. Perform the calculation:
[tex]\[ \text{Hydrogen volume} = 0.10824 \times 55 = 5.9532 \][/tex]
6. Round the result to two decimal places:
- The volume of hydrogen in the sample is [tex]\( 5.95 \)[/tex] ml.
Therefore, there are [tex]\( \boxed{5.95} \)[/tex] ml of hydrogen in the sample.
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