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Match the system of equations on the left with the appropriate solution on the right.

[tex]\[
\begin{array}{rl}
1. & 4x - 3y = -1 \\
& -3x + 4y = 6 \\
2. & 3x - 2y = -1 \\
& -x + 2y = 3 \\
3. & 3x + 6y = 6 \\
& 2x + 4y = -4 \\
4. & -3x + 6y = -3 \\
& 5x - 10y = 5 \\
\end{array}
\][/tex]

A. [tex]\((-2, 0)\)[/tex]
B. Infinite number of solutions
C. No solution

---

Match the following systems of equations with the solutions provided above.


Sagot :

Let's solve each system of equations step by step and match them with the appropriate solutions, which are [tex]\((-2, 0)\)[/tex], infinite number of solutions, or no solution.

### 1. System:
[tex]\[ 4x - 3y = -1 \][/tex]
[tex]\[ -3x + 4y = 6 \][/tex]

Multiply the first equation by 3 and the second by 4 to align the coefficients:

[tex]\[ 12x - 9y = -3 \][/tex]
[tex]\[ -12x + 16y = 24 \][/tex]

Adding these equations:
[tex]\[ 12x - 9y - 12x + 16y = -3 + 24 \][/tex]
[tex]\[ 7y = 21 \][/tex]
[tex]\[ y = 3 \][/tex]

Substituting [tex]\( y = 3 \)[/tex] back into the first equation:
[tex]\[ 4x - 3(3) = -1 \][/tex]
[tex]\[ 4x - 9 = -1 \][/tex]
[tex]\[ 4x = 8 \][/tex]
[tex]\[ x = 2 \][/tex]

Solution: [tex]\((2, 3)\)[/tex]

### 2. System:
[tex]\[ 3x - 2y = -1 \][/tex]
[tex]\[ -x + 2y = 3 \][/tex]

Add both equations:
[tex]\[ 3x - 2y - x + 2y = -1 + 3 \][/tex]
[tex]\[ 2x = 2 \][/tex]
[tex]\[ x = 1 \][/tex]

Substitute [tex]\( x = 1 \)[/tex] back into the second equation:
[tex]\[ -1 + 2y = 3 \][/tex]
[tex]\[ 2y = 4 \][/tex]
[tex]\[ y = 2 \][/tex]

Solution: [tex]\((1, 2)\)[/tex]

### 3. System:
[tex]\[ 3x + 6y = 6 \][/tex]
[tex]\[ 2x + 4y = -4 \][/tex]

Notice both equations are multiples of each other:

[tex]\[ \text{Divide the first by 3:} \][/tex]
[tex]\[ x + 2y = 2 \][/tex]

[tex]\[ \text{Divide the second by 2:} \][/tex]
[tex]\[ x + 2y = -2 \][/tex]

Contradiction as the same left-hand side equals different right-hand sides. Hence, there is no solution.

### 4. System:
[tex]\[ -3x + 6y = -3 \][/tex]
[tex]\[ 5x - 10y = 5 \][/tex]

Divide both equations by their leading coefficients:

[tex]\[ -3x + 6y = -3 \][/tex]
[tex]\[ x - 2y = -1 \][/tex] (Dividing the first equation by -3)

[tex]\[ 5x - 10y = 5 \][/tex]
[tex]\[ x - 2y = 1 \][/tex] (Dividing the second equation by 5)

Contradiction as the same left-hand side equals different right-hand sides. Hence, there are infinite solutions.

### Summary:
- [tex]\((2, 3)\)[/tex]: No match found from the provided solutions.
- [tex]\((1, 2)\)[/tex]: No match found from the provided solutions.
- The pair [tex]\(\ 4x - 3y = -1 \)[/tex][tex]\( -3 x + 4 y =6 matches: User error - The pair \(3 x - 2 y = -1 \)[/tex] [tex]\(-x + 2 y = 3\)[/tex]
matches: User error
with [tex]\(x=-2, y=0\)[/tex]}: No match found from the provided solutions.
Notice both equations are multiples of each other:

Hence,
- The pair [tex]\(\ 3x + 6y = 6 and {2 x + 4 y =-4\)[/tex] matches Infinite number of solutions.

- The pair [tex]\( -3 x + 6 y=-3 \)[/tex] and {[tex]\(}5 x-10 y=5\)[/tex] No Solution.