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Sagot :
Let's solve each part step by step:
### Section 1
1. Find:
(i) [tex]\(0.2 \times 6\)[/tex]:
[tex]\[0.2 \times 6 = 1.2\][/tex]
(ii) [tex]\(8 \times 4.6\)[/tex]:
[tex]\[8 \times 4.6 = 36.8\][/tex]
(iii) [tex]\(2.71 \times 5\)[/tex]:
[tex]\[2.71 \times 5 = 13.55\][/tex]
(iv) 201:
[tex]\[201 = 201\][/tex]
(v) [tex]\(0.05 \times 7\)[/tex]:
[tex]\[0.05 \times 7 = 0.35\][/tex]
(vi) [tex]\(211.02 \times 4\)[/tex]:
[tex]\[211.02 \times 4 = 844.08\][/tex]
(vii) [tex]\(2 \times 0.86\)[/tex]:
[tex]\[2 \times 0.86 = 1.72\][/tex]
So, the results for Section 1 are:
[tex]\[ (1.2, 36.8, 13.55, 201, 0.35, 844.08, 1.72) \][/tex]
### Section 2
2. Find the area of a rectangle whose length is 5.7 cm and breadth is 3 cm:
[tex]\[ \text{Area} = \text{length} \times \text{breadth} = 5.7 \times 3 = 17.1 \text{ cm}^2 \][/tex]
### Section 3
3. Find:
(i) [tex]\(1.3 \times 10\)[/tex]:
[tex]\[1.3 \times 10 = 13.0\][/tex]
(ii) [tex]\(36.8 \times 10\)[/tex]:
[tex]\[36.8 \times 10 = 368.0\][/tex]
(iii) [tex]\(153.7 \times 10\)[/tex]:
[tex]\[153.7 \times 10 = 1537.0\][/tex]
(iv) [tex]\(168.07 \times 10\)[/tex]:
[tex]\[168.07 \times 10 = 1680.7\][/tex]
(v) [tex]\(31.1 \times 100\)[/tex]:
[tex]\[31.1 \times 100 = 3110.0\][/tex]
(vi) [tex]\(156.1 \times 100\)[/tex]:
[tex]\[156.1 \times 100 = 15610.0\][/tex]
(vii) [tex]\(3.62 \times 100\)[/tex]:
[tex]\[3.62 \times 100 = 362.0\][/tex]
(viii) [tex]\(43.07 \times 100\)[/tex]:
[tex]\[43.07 \times 100 = 4307.0\][/tex]
(ix) [tex]\(0.5 \times 10\)[/tex]:
[tex]\[0.5 \times 10 = 5.0\][/tex]
(x) [tex]\(0.08 \times 10\)[/tex]:
[tex]\[0.08 \times 10 = 0.8\][/tex]
(xi) [tex]\(0.9 \times 100\)[/tex]:
[tex]\[0.9 \times 100 = 90.0\][/tex]
(xii) [tex]\(0.03 \times 1000\)[/tex]:
[tex]\[0.03 \times 1000 = 30.0\][/tex]
So, the results for Section 3 are:
[tex]\[ (13.0, 368.0, 1537.0, 1680.7, 3110.0, 15610.0, 362.0, 4307.0, 5.0, 0.8, 90.0, 30.0) \][/tex]
### Section 4
4. A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol?
[tex]\[ \text{Total distance} = \text{distance per litre} \times \text{litres} = 55.3 \times 10 = 553.0 \text{ km} \][/tex]
### Section 5
5. Find:
(i) [tex]\(2.5 \times 0.3\)[/tex]:
[tex]\[2.5 \times 0.3 = 0.75\][/tex]
(ii) [tex]\(0.1 \times 51.7\)[/tex]:
[tex]\[0.1 \times 51.7 = 5.17\][/tex]
(iii) [tex]\(0.2 \times 316.8\)[/tex]:
[tex]\[0.2 \times 316.8 = 63.36\][/tex]
(iv) [tex]\(1.3 \times x\)[/tex]:
[tex]\[ \text{Cannot be calculated without knowing } x \][/tex]
(v) [tex]\(0.5 \times 0.05\)[/tex]:
[tex]\[0.5 \times 0.05 = 0.025\][/tex]
(vi) [tex]\(11.2 \times 0.15\)[/tex]:
[tex]\[11.2 \times 0.15 = 1.68\][/tex]
(vii) [tex]\(1.07 \times 0.02\)[/tex]:
[tex]\[1.07 \times 0.02 = 0.0214\][/tex]
(viii) [tex]\(10.05 \times 1.05\)[/tex]:
[tex]\[10.05 \times 1.05 = 10.5525\][/tex]
(ix) [tex]\(101.01 \times 0.01\)[/tex]:
[tex]\[101.01 \times 0.01 = 1.0101\][/tex]
(x) [tex]\(100.01 \times 1.1\)[/tex]:
[tex]\[100.01 \times 1.1 = 110.011\][/tex]
So, the results for Section 5 are:
[tex]\[ (0.75, 5.17, 63.36, \text{None}, 0.025, 1.68, 0.0214, 10.5525, 1.0101, 110.011) \][/tex]
To summarize:
- Section 1: [tex]\((1.2, 36.8, 13.55, 201, 0.35, 844.08, 1.72)\)[/tex]
- Area of rectangle: [tex]\(17.1 \text{ cm}^2\)[/tex]
- Section 3: [tex]\((13.0, 368.0, 1537.0, 1680.7, 3110.0, 15610.0, 362.0, 4307.0, 5.0, 0.8, 90.0, 30.0)\)[/tex]
- Distance covered in 10 litres: [tex]\(553.0 \text{ km}\)[/tex]
- Section 5: [tex]\((0.75, 5.17, 63.36, \text{None}, 0.025, 1.68, 0.0214, 10.5525, 1.0101, 110.011)\)[/tex]
### Section 1
1. Find:
(i) [tex]\(0.2 \times 6\)[/tex]:
[tex]\[0.2 \times 6 = 1.2\][/tex]
(ii) [tex]\(8 \times 4.6\)[/tex]:
[tex]\[8 \times 4.6 = 36.8\][/tex]
(iii) [tex]\(2.71 \times 5\)[/tex]:
[tex]\[2.71 \times 5 = 13.55\][/tex]
(iv) 201:
[tex]\[201 = 201\][/tex]
(v) [tex]\(0.05 \times 7\)[/tex]:
[tex]\[0.05 \times 7 = 0.35\][/tex]
(vi) [tex]\(211.02 \times 4\)[/tex]:
[tex]\[211.02 \times 4 = 844.08\][/tex]
(vii) [tex]\(2 \times 0.86\)[/tex]:
[tex]\[2 \times 0.86 = 1.72\][/tex]
So, the results for Section 1 are:
[tex]\[ (1.2, 36.8, 13.55, 201, 0.35, 844.08, 1.72) \][/tex]
### Section 2
2. Find the area of a rectangle whose length is 5.7 cm and breadth is 3 cm:
[tex]\[ \text{Area} = \text{length} \times \text{breadth} = 5.7 \times 3 = 17.1 \text{ cm}^2 \][/tex]
### Section 3
3. Find:
(i) [tex]\(1.3 \times 10\)[/tex]:
[tex]\[1.3 \times 10 = 13.0\][/tex]
(ii) [tex]\(36.8 \times 10\)[/tex]:
[tex]\[36.8 \times 10 = 368.0\][/tex]
(iii) [tex]\(153.7 \times 10\)[/tex]:
[tex]\[153.7 \times 10 = 1537.0\][/tex]
(iv) [tex]\(168.07 \times 10\)[/tex]:
[tex]\[168.07 \times 10 = 1680.7\][/tex]
(v) [tex]\(31.1 \times 100\)[/tex]:
[tex]\[31.1 \times 100 = 3110.0\][/tex]
(vi) [tex]\(156.1 \times 100\)[/tex]:
[tex]\[156.1 \times 100 = 15610.0\][/tex]
(vii) [tex]\(3.62 \times 100\)[/tex]:
[tex]\[3.62 \times 100 = 362.0\][/tex]
(viii) [tex]\(43.07 \times 100\)[/tex]:
[tex]\[43.07 \times 100 = 4307.0\][/tex]
(ix) [tex]\(0.5 \times 10\)[/tex]:
[tex]\[0.5 \times 10 = 5.0\][/tex]
(x) [tex]\(0.08 \times 10\)[/tex]:
[tex]\[0.08 \times 10 = 0.8\][/tex]
(xi) [tex]\(0.9 \times 100\)[/tex]:
[tex]\[0.9 \times 100 = 90.0\][/tex]
(xii) [tex]\(0.03 \times 1000\)[/tex]:
[tex]\[0.03 \times 1000 = 30.0\][/tex]
So, the results for Section 3 are:
[tex]\[ (13.0, 368.0, 1537.0, 1680.7, 3110.0, 15610.0, 362.0, 4307.0, 5.0, 0.8, 90.0, 30.0) \][/tex]
### Section 4
4. A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol?
[tex]\[ \text{Total distance} = \text{distance per litre} \times \text{litres} = 55.3 \times 10 = 553.0 \text{ km} \][/tex]
### Section 5
5. Find:
(i) [tex]\(2.5 \times 0.3\)[/tex]:
[tex]\[2.5 \times 0.3 = 0.75\][/tex]
(ii) [tex]\(0.1 \times 51.7\)[/tex]:
[tex]\[0.1 \times 51.7 = 5.17\][/tex]
(iii) [tex]\(0.2 \times 316.8\)[/tex]:
[tex]\[0.2 \times 316.8 = 63.36\][/tex]
(iv) [tex]\(1.3 \times x\)[/tex]:
[tex]\[ \text{Cannot be calculated without knowing } x \][/tex]
(v) [tex]\(0.5 \times 0.05\)[/tex]:
[tex]\[0.5 \times 0.05 = 0.025\][/tex]
(vi) [tex]\(11.2 \times 0.15\)[/tex]:
[tex]\[11.2 \times 0.15 = 1.68\][/tex]
(vii) [tex]\(1.07 \times 0.02\)[/tex]:
[tex]\[1.07 \times 0.02 = 0.0214\][/tex]
(viii) [tex]\(10.05 \times 1.05\)[/tex]:
[tex]\[10.05 \times 1.05 = 10.5525\][/tex]
(ix) [tex]\(101.01 \times 0.01\)[/tex]:
[tex]\[101.01 \times 0.01 = 1.0101\][/tex]
(x) [tex]\(100.01 \times 1.1\)[/tex]:
[tex]\[100.01 \times 1.1 = 110.011\][/tex]
So, the results for Section 5 are:
[tex]\[ (0.75, 5.17, 63.36, \text{None}, 0.025, 1.68, 0.0214, 10.5525, 1.0101, 110.011) \][/tex]
To summarize:
- Section 1: [tex]\((1.2, 36.8, 13.55, 201, 0.35, 844.08, 1.72)\)[/tex]
- Area of rectangle: [tex]\(17.1 \text{ cm}^2\)[/tex]
- Section 3: [tex]\((13.0, 368.0, 1537.0, 1680.7, 3110.0, 15610.0, 362.0, 4307.0, 5.0, 0.8, 90.0, 30.0)\)[/tex]
- Distance covered in 10 litres: [tex]\(553.0 \text{ km}\)[/tex]
- Section 5: [tex]\((0.75, 5.17, 63.36, \text{None}, 0.025, 1.68, 0.0214, 10.5525, 1.0101, 110.011)\)[/tex]
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