Get the information you need quickly and easily with IDNLearn.com. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.
Sagot :
To solve the problem, we start with the given equation
[tex]\[ \sin A + \csc A = 3 \][/tex]
Recall that [tex]\(\csc A = \frac{1}{\sin A}\)[/tex]. Substituting this into the equation, we get:
[tex]\[ \sin A + \frac{1}{\sin A} = 3 \][/tex]
Let [tex]\(\sin A = x\)[/tex]. Then the equation becomes:
[tex]\[ x + \frac{1}{x} = 3 \][/tex]
Multiplying through by [tex]\(x\)[/tex], we get:
[tex]\[ x^2 + 1 = 3x \][/tex]
Rearranging the terms gives us a quadratic equation:
[tex]\[ x^2 - 3x + 1 = 0 \][/tex]
We can solve this quadratic equation using the quadratic formula [tex]\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)[/tex], where [tex]\(a = 1\)[/tex], [tex]\(b = -3\)[/tex], and [tex]\(c = 1\)[/tex]. Substituting these values in, we get:
[tex]\[ x = \frac{3 \pm \sqrt{9 - 4}}{2} \][/tex]
[tex]\[ x = \frac{3 \pm \sqrt{5}}{2} \][/tex]
So, the solutions for [tex]\(x\)[/tex] are:
[tex]\[ x = \frac{3 + \sqrt{5}}{2} \quad \text{and} \quad x = \frac{3 - \sqrt{5}}{2} \][/tex]
These solutions correspond to:
[tex]\[ \sin A = \frac{3 + \sqrt{5}}{2} \quad \text{and} \quad \sin A = \frac{3 - \sqrt{5}}{2} \][/tex]
Next, we need to evaluate [tex]\(\frac{\sin^4 A + 1}{\sin^2 A}\)[/tex] for each value of [tex]\(x\)[/tex].
Starting with the first solution, [tex]\(\sin A = \frac{3 + \sqrt{5}}{2}\)[/tex]:
[tex]\[ \frac{\left(\frac{3 + \sqrt{5}}{2}\right)^4 + 1}{\left(\frac{3 + \sqrt{5}}{2}\right)^2} \][/tex]
For the second solution, [tex]\(\sin A = \frac{3 - \sqrt{5}}{2}\)[/tex]:
[tex]\[ \frac{\left(\frac{3 - \sqrt{5}}{2}\right)^4 + 1}{\left(\frac{3 - \sqrt{5}}{2}\right)^2} \][/tex]
After solving these for the expressions, we get:
Simplifying these terms yields the results that were previously mentioned. Thus, the final solutions are derived as follows, without showing intermediate steps for the algebraic polynomials:
[tex]\[ \frac{(\sin A)^4 + 1}{(\sin A)^2} \][/tex]
For the solutions [tex]\(\sin A = \frac{3 + \sqrt{5}}{2}\)[/tex] and [tex]\(\sin A = \frac{3 - \sqrt{5}}{2}\)[/tex], the detailed stepwise solutions will lead us to the acceptable results:
[tex]\[ 1 + \left(\frac{3 + \sqrt{5}}{2}\right)^2 \quad \text{and} \quad \left(\frac{3 - \sqrt{5}}{2}^2\right) + 1 \][/tex]
[tex]\[ \sin A + \csc A = 3 \][/tex]
Recall that [tex]\(\csc A = \frac{1}{\sin A}\)[/tex]. Substituting this into the equation, we get:
[tex]\[ \sin A + \frac{1}{\sin A} = 3 \][/tex]
Let [tex]\(\sin A = x\)[/tex]. Then the equation becomes:
[tex]\[ x + \frac{1}{x} = 3 \][/tex]
Multiplying through by [tex]\(x\)[/tex], we get:
[tex]\[ x^2 + 1 = 3x \][/tex]
Rearranging the terms gives us a quadratic equation:
[tex]\[ x^2 - 3x + 1 = 0 \][/tex]
We can solve this quadratic equation using the quadratic formula [tex]\(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)[/tex], where [tex]\(a = 1\)[/tex], [tex]\(b = -3\)[/tex], and [tex]\(c = 1\)[/tex]. Substituting these values in, we get:
[tex]\[ x = \frac{3 \pm \sqrt{9 - 4}}{2} \][/tex]
[tex]\[ x = \frac{3 \pm \sqrt{5}}{2} \][/tex]
So, the solutions for [tex]\(x\)[/tex] are:
[tex]\[ x = \frac{3 + \sqrt{5}}{2} \quad \text{and} \quad x = \frac{3 - \sqrt{5}}{2} \][/tex]
These solutions correspond to:
[tex]\[ \sin A = \frac{3 + \sqrt{5}}{2} \quad \text{and} \quad \sin A = \frac{3 - \sqrt{5}}{2} \][/tex]
Next, we need to evaluate [tex]\(\frac{\sin^4 A + 1}{\sin^2 A}\)[/tex] for each value of [tex]\(x\)[/tex].
Starting with the first solution, [tex]\(\sin A = \frac{3 + \sqrt{5}}{2}\)[/tex]:
[tex]\[ \frac{\left(\frac{3 + \sqrt{5}}{2}\right)^4 + 1}{\left(\frac{3 + \sqrt{5}}{2}\right)^2} \][/tex]
For the second solution, [tex]\(\sin A = \frac{3 - \sqrt{5}}{2}\)[/tex]:
[tex]\[ \frac{\left(\frac{3 - \sqrt{5}}{2}\right)^4 + 1}{\left(\frac{3 - \sqrt{5}}{2}\right)^2} \][/tex]
After solving these for the expressions, we get:
Simplifying these terms yields the results that were previously mentioned. Thus, the final solutions are derived as follows, without showing intermediate steps for the algebraic polynomials:
[tex]\[ \frac{(\sin A)^4 + 1}{(\sin A)^2} \][/tex]
For the solutions [tex]\(\sin A = \frac{3 + \sqrt{5}}{2}\)[/tex] and [tex]\(\sin A = \frac{3 - \sqrt{5}}{2}\)[/tex], the detailed stepwise solutions will lead us to the acceptable results:
[tex]\[ 1 + \left(\frac{3 + \sqrt{5}}{2}\right)^2 \quad \text{and} \quad \left(\frac{3 - \sqrt{5}}{2}^2\right) + 1 \][/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.