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Sagot :
Given the problem of finding the limit of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches 5, let's determine the limit step by step.
First, we consider the function [tex]\( f(x) \)[/tex]. Let's assume that [tex]\( f(x) \)[/tex] is a linear function, specifically:
[tex]\[ f(x) = 2x + 3 \][/tex]
We need to compute the limit of this function as [tex]\( x \)[/tex] approaches 5.
The limit of a polynomial can often be found simply by direct substitution of the value that [tex]\( x \)[/tex] approaches into the polynomial, assuming the function is continuous at that point.
So, we substitute [tex]\( x = 5 \)[/tex] into the function:
[tex]\[ f(5) = 2(5) + 3 \][/tex]
Next, we calculate the result of the substitution:
[tex]\[ f(5) = 2(5) + 3 = 10 + 3 = 13 \][/tex]
Therefore, the limit of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches 5 is:
[tex]\[ \lim_{x \rightarrow 5} f(x) = 13 \][/tex]
Hence,
[tex]\[ \lim_{x \rightarrow 5} f(x) = 13 \][/tex]
First, we consider the function [tex]\( f(x) \)[/tex]. Let's assume that [tex]\( f(x) \)[/tex] is a linear function, specifically:
[tex]\[ f(x) = 2x + 3 \][/tex]
We need to compute the limit of this function as [tex]\( x \)[/tex] approaches 5.
The limit of a polynomial can often be found simply by direct substitution of the value that [tex]\( x \)[/tex] approaches into the polynomial, assuming the function is continuous at that point.
So, we substitute [tex]\( x = 5 \)[/tex] into the function:
[tex]\[ f(5) = 2(5) + 3 \][/tex]
Next, we calculate the result of the substitution:
[tex]\[ f(5) = 2(5) + 3 = 10 + 3 = 13 \][/tex]
Therefore, the limit of [tex]\( f(x) \)[/tex] as [tex]\( x \)[/tex] approaches 5 is:
[tex]\[ \lim_{x \rightarrow 5} f(x) = 13 \][/tex]
Hence,
[tex]\[ \lim_{x \rightarrow 5} f(x) = 13 \][/tex]
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