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Sagot :
To find the rate of the reaction, we can use the provided rate equation:
[tex]\[ \text{Rate} = k[A]^2[B]^2 \][/tex]
Given the values:
- [tex]\( k = 0.1 \, \text{(rate constant)} \)[/tex]
- [tex]\( [A] = 1 \, \text{M} \)[/tex]
- [tex]\( [B] = 2 \, \text{M} \)[/tex]
Let's substitute these values into the rate equation step-by-step:
1. Substitute the concentration values and the rate constant into the rate equation:
[tex]\[ \text{Rate} = 0.1 \times (1)^2 \times (2)^2 \][/tex]
2. Calculate [tex]\( [A]^2 \)[/tex]:
[tex]\[ [A]^2 = (1)^2 = 1 \][/tex]
3. Calculate [tex]\( [B]^2 \)[/tex]:
[tex]\[ [B]^2 = (2)^2 = 4 \][/tex]
4. Multiply all the terms together:
[tex]\[ \text{Rate} = 0.1 \times 1 \times 4 = 0.4 \][/tex]
So, the rate of the reaction is:
[tex]\[ \text{Rate} = 0.4 \, \text{(mol/L)/s} \][/tex]
Therefore, the correct answer is:
D. [tex]\( 0.4 \, \text{(mol/L)/s} \)[/tex]
[tex]\[ \text{Rate} = k[A]^2[B]^2 \][/tex]
Given the values:
- [tex]\( k = 0.1 \, \text{(rate constant)} \)[/tex]
- [tex]\( [A] = 1 \, \text{M} \)[/tex]
- [tex]\( [B] = 2 \, \text{M} \)[/tex]
Let's substitute these values into the rate equation step-by-step:
1. Substitute the concentration values and the rate constant into the rate equation:
[tex]\[ \text{Rate} = 0.1 \times (1)^2 \times (2)^2 \][/tex]
2. Calculate [tex]\( [A]^2 \)[/tex]:
[tex]\[ [A]^2 = (1)^2 = 1 \][/tex]
3. Calculate [tex]\( [B]^2 \)[/tex]:
[tex]\[ [B]^2 = (2)^2 = 4 \][/tex]
4. Multiply all the terms together:
[tex]\[ \text{Rate} = 0.1 \times 1 \times 4 = 0.4 \][/tex]
So, the rate of the reaction is:
[tex]\[ \text{Rate} = 0.4 \, \text{(mol/L)/s} \][/tex]
Therefore, the correct answer is:
D. [tex]\( 0.4 \, \text{(mol/L)/s} \)[/tex]
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