Discover new information and get your questions answered with IDNLearn.com. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.
Sagot :
To solve the quadratic equation [tex]\(x^2 - 6x + 4 = 0\)[/tex] by completing the square, follow these steps:
1. Start with the given equation:
[tex]\[ x^2 - 6x + 4 = 0 \][/tex]
2. Move the constant term to the right side:
[tex]\[ x^2 - 6x = -4 \][/tex]
3. Complete the square on the left side:
- Take half of the coefficient of [tex]\(x\)[/tex] (which is [tex]\(-6\)[/tex]), divide by 2, and square it:
[tex]\[ \left(\frac{-6}{2}\right)^2 = 9 \][/tex]
- Add and subtract this value to/from the left side:
[tex]\[ x^2 - 6x + 9 - 9 = -4 \][/tex]
- Rearrange the equation:
[tex]\[ (x - 3)^2 - 9 = -4 \][/tex]
4. Move the constant term [tex]\(-9\)[/tex] to the right side to isolate the square term:
[tex]\[ (x - 3)^2 = 5 \][/tex]
5. Take the square root of both sides:
[tex]\[ x - 3 = \pm \sqrt{5} \][/tex]
6. Solve for [tex]\(x\)[/tex]:
[tex]\[ x = 3 + \sqrt{5} \quad \text{or} \quad x = 3 - \sqrt{5} \][/tex]
So, the solutions for the quadratic equation [tex]\(x^2 - 6x + 4 = 0\)[/tex] are:
[tex]\[ x = 3 + \sqrt{5} \quad \text{and} \quad x = 3 - \sqrt{5} \][/tex]
1. Start with the given equation:
[tex]\[ x^2 - 6x + 4 = 0 \][/tex]
2. Move the constant term to the right side:
[tex]\[ x^2 - 6x = -4 \][/tex]
3. Complete the square on the left side:
- Take half of the coefficient of [tex]\(x\)[/tex] (which is [tex]\(-6\)[/tex]), divide by 2, and square it:
[tex]\[ \left(\frac{-6}{2}\right)^2 = 9 \][/tex]
- Add and subtract this value to/from the left side:
[tex]\[ x^2 - 6x + 9 - 9 = -4 \][/tex]
- Rearrange the equation:
[tex]\[ (x - 3)^2 - 9 = -4 \][/tex]
4. Move the constant term [tex]\(-9\)[/tex] to the right side to isolate the square term:
[tex]\[ (x - 3)^2 = 5 \][/tex]
5. Take the square root of both sides:
[tex]\[ x - 3 = \pm \sqrt{5} \][/tex]
6. Solve for [tex]\(x\)[/tex]:
[tex]\[ x = 3 + \sqrt{5} \quad \text{or} \quad x = 3 - \sqrt{5} \][/tex]
So, the solutions for the quadratic equation [tex]\(x^2 - 6x + 4 = 0\)[/tex] are:
[tex]\[ x = 3 + \sqrt{5} \quad \text{and} \quad x = 3 - \sqrt{5} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.