Join IDNLearn.com and start getting the answers you've been searching for. Discover prompt and accurate responses from our experts, ensuring you get the information you need quickly.

The general form for the equation of a circle is shown:

[tex]\[ 3x^2 + 3y^2 + 30x - 24y - 12 = 0 \][/tex]

What is the standard form of the equation?

Type the correct answer in the box. Use numerals instead of words.

[tex]\[ (x + \square)^2 + (y + \square)^2 = \square \][/tex]


Sagot :

To convert the given general form of the circle equation into the standard form, we'll go through the process step-by-step.

Given equation:
[tex]\[ 3x^2 + 3y^2 + 30x - 24y - 12 = 0 \][/tex]

1. Simplify the equation: Divide the entire equation by 3 to make it easier to work with.

[tex]\[ x^2 + y^2 + 10x - 8y - 4 = 0 \][/tex]

2. Rearrange the terms: Group the [tex]\(x\)[/tex] terms together and the [tex]\(y\)[/tex] terms together.

[tex]\[ (x^2 + 10x) + (y^2 - 8y) = 4 \][/tex]

3. Complete the square for [tex]\(x\)[/tex]:

- Take the coefficient of [tex]\(x\)[/tex], which is 10, divide it by 2 to get 5, and then square it to get 25.
- Add and subtract 25 within the [tex]\(x\)[/tex] terms.

[tex]\[ (x^2 + 10x + 25 - 25) + (y^2 - 8y) = 4 \][/tex]

[tex]\[ (x + 5)^2 - 25 + (y^2 - 8y) = 4 \][/tex]

4. Complete the square for [tex]\(y\)[/tex]:

- Take the coefficient of [tex]\(y\)[/tex], which is -8, divide it by 2 to get -4, and then square it to get 16.
- Add and subtract 16 within the [tex]\(y\)[/tex] terms.

[tex]\[ (x + 5)^2 - 25 + (y^2 - 8y + 16 - 16) = 4 \][/tex]

[tex]\[ (x + 5)^2 - 25 + (y - 4)^2 - 16 = 4 \][/tex]

5. Combine constants on the right side:

[tex]\[ (x + 5)^2 + (y - 4)^2 - 41 = 4 \][/tex]

[tex]\[ (x + 5)^2 + (y - 4)^2 = 45 \][/tex]

Thus, the standard form of the equation of the circle is:

[tex]\[ (x + 5)^2 + (y - 4)^2 = 45 \][/tex]

So the filled standard form equation is:

[tex]\[ (x + \boxed{5})^2 + (y + \boxed{-4})^2 = \boxed{45} \][/tex]