IDNLearn.com provides a reliable platform for finding accurate and timely answers. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.
Sagot :
To determine if the triangle with side lengths 2 inches, 5 inches, and 4 inches is an acute triangle, we need to follow a systematic approach:
1. Understand acute triangles:
- A triangle is acute if all its interior angles are less than 90 degrees.
- For a triangle with sides [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] (where [tex]\(c\)[/tex] is the longest side), it is acute if the sum of the squares of the two smaller sides is greater than the square of the longest side, i.e., [tex]\(a^2 + b^2 > c^2\)[/tex].
2. Identify the sides:
- Here, [tex]\(a = 2\)[/tex] inches, [tex]\(b = 4\)[/tex] inches, and [tex]\(c = 5\)[/tex] inches (the longest side).
3. Apply the conditions for an acute triangle:
- We need to verify if the inequality [tex]\(a^2 + b^2 > c^2\)[/tex] holds.
4. Compute the squares:
- Calculate [tex]\(a^2\)[/tex]: [tex]\(2^2 = 4\)[/tex]
- Calculate [tex]\(b^2\)[/tex]: [tex]\(4^2 = 16\)[/tex]
- Calculate [tex]\(c^2\)[/tex]: [tex]\(5^2 = 25\)[/tex]
5. Check the condition:
- Compute [tex]\(a^2 + b^2\)[/tex]: [tex]\(4 + 16 = 20\)[/tex]
- Compare with [tex]\(c^2\)[/tex]: [tex]\(20 < 25\)[/tex]
Since [tex]\(a^2 + b^2\)[/tex] is less than [tex]\(c^2\)[/tex] ([tex]\(20 < 25\)[/tex]), the condition for an acute triangle is not met.
Thus, the best explanation is:
- The triangle is not acute because [tex]\(2^2 + 4^2 < 5^2\)[/tex].
1. Understand acute triangles:
- A triangle is acute if all its interior angles are less than 90 degrees.
- For a triangle with sides [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] (where [tex]\(c\)[/tex] is the longest side), it is acute if the sum of the squares of the two smaller sides is greater than the square of the longest side, i.e., [tex]\(a^2 + b^2 > c^2\)[/tex].
2. Identify the sides:
- Here, [tex]\(a = 2\)[/tex] inches, [tex]\(b = 4\)[/tex] inches, and [tex]\(c = 5\)[/tex] inches (the longest side).
3. Apply the conditions for an acute triangle:
- We need to verify if the inequality [tex]\(a^2 + b^2 > c^2\)[/tex] holds.
4. Compute the squares:
- Calculate [tex]\(a^2\)[/tex]: [tex]\(2^2 = 4\)[/tex]
- Calculate [tex]\(b^2\)[/tex]: [tex]\(4^2 = 16\)[/tex]
- Calculate [tex]\(c^2\)[/tex]: [tex]\(5^2 = 25\)[/tex]
5. Check the condition:
- Compute [tex]\(a^2 + b^2\)[/tex]: [tex]\(4 + 16 = 20\)[/tex]
- Compare with [tex]\(c^2\)[/tex]: [tex]\(20 < 25\)[/tex]
Since [tex]\(a^2 + b^2\)[/tex] is less than [tex]\(c^2\)[/tex] ([tex]\(20 < 25\)[/tex]), the condition for an acute triangle is not met.
Thus, the best explanation is:
- The triangle is not acute because [tex]\(2^2 + 4^2 < 5^2\)[/tex].
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.