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Consider continuous functions [tex]\( f, g, h \)[/tex], and [tex]\( k \)[/tex]. Then complete the statements.

\begin{tabular}{|c|c|}
\hline
[tex]$x$[/tex] & [tex]$g(x)$[/tex] \\
\hline
-2 & 76 \\
\hline
-1 & 11 \\
\hline
0 & -4 \\
\hline
1 & -5 \\
\hline
2 & -4 \\
\hline
3 & 11 \\
\hline
\end{tabular}

Function [tex]\( h \)[/tex] is two times the square of the difference of [tex]\( x \)[/tex] and 1.
[tex]\[
h(x) = 2(x - 1)^2
\][/tex]

[tex]\[
k(x) = x^4 + 2x^2 + 8x - 4
\][/tex]

Select the correct answer from each drop-down.

The function that has the least minimum value is function [tex]\(\square\)[/tex].


Sagot :

To determine which function among [tex]\( g, h, \)[/tex] and [tex]\( k \)[/tex] has the least minimum value, we need to analyze the minimum values of each function over the interval from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex].

1. Evaluating [tex]\( g(x) \)[/tex]:

Given the table of values for [tex]\( g(x) \)[/tex]:
[tex]\[ \begin{array}{|c|c|} \hline x & g(x) \\ \hline -2 & 76 \\ -1 & 11 \\ 0 & -4 \\ 1 & -5 \\ 2 & -4 \\ 3 & 11 \\ \hline \end{array} \][/tex]
The minimum value of [tex]\( g(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(-5\)[/tex].

2. Evaluating [tex]\( h(x) \)[/tex]:

The function [tex]\( h(x) \)[/tex] is defined as:
[tex]\[ h(x) = 2(x - 1)^2 \][/tex]
To find the minimum value of [tex]\( h(x) \)[/tex] over the interval [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex]:
[tex]\[ \begin{aligned} h(-2) &= 2(-2 - 1)^2 = 2( -3)^2 = 2 \times 9 = 18, \\ h(-1) &= 2(-1 - 1)^2 = 2( -2)^2 = 2 \times 4 = 8, \\ h(0) &= 2(0 - 1)^2 = 2( -1)^2 = 2 \times 1 = 2, \\ h(1) &= 2(1 - 1)^2 = 2( 0)^2 = 2 \times 0 = 0, \\ h(2) &= 2(2 - 1)^2 = 2( 1)^2 = 2 \times 1 = 2, \\ h(3) &= 2(3 - 1)^2 = 2( 2)^2 = 2 \times 4 = 8. \end{aligned} \][/tex]
The minimum value of [tex]\( h(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(0\)[/tex].

3. Evaluating [tex]\( k(x) \)[/tex]:

The function [tex]\( k(x) \)[/tex] is defined as:
[tex]\[ k(x) = x^4 + 2x^2 + 8x - 4 \][/tex]
To find the minimum value of [tex]\( k(x) \)[/tex] over the interval [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex]:
[tex]\[ \begin{aligned} k(-2) &= (-2)^4 + 2(-2)^2 + 8(-2) - 4 = 16 + 8 - 16 - 4 = 4, \\ k(-1) &= (-1)^4 + 2(-1)^2 + 8(-1) - 4 = 1 + 2 - 8 - 4 = -9, \\ k(0) &= 0^4 + 2(0)^2 + 8(0) - 4 = -4, \\ k(1) &= 1^4 + 2(1)^2 + 8(1) - 4 = 1 + 2 + 8 - 4 = 7, \\ k(2) &= 2^4 + 2(2)^2 + 8(2) - 4 = 16 + 8 + 16 - 4 = 36, \\ k(3) &= 3^4 + 2(3)^2 + 8(3) - 4 = 81 + 18 + 24 - 4 = 119. \end{aligned} \][/tex]
The minimum value of [tex]\( k(x) \)[/tex] from [tex]\( x = -2 \)[/tex] to [tex]\( x = 3 \)[/tex] is [tex]\(-9\)[/tex].

Comparing the minimum values:
- Minimum of [tex]\( g(x) \)[/tex]: [tex]\(-5\)[/tex]
- Minimum of [tex]\( h(x) \)[/tex]: [tex]\(0\)[/tex]
- Minimum of [tex]\( k(x) \)[/tex]: [tex]\(-9\)[/tex]

The function that has the least minimum value is [tex]\( k \)[/tex].

So, the correct answer is:
The function that has the least minimum value is function [tex]\( \boxed{k} \)[/tex].