Connect with a community of experts and enthusiasts on IDNLearn.com. Get accurate and comprehensive answers from our network of experienced professionals.
Sagot :
To balance the chemical equation for the reaction between a weak base (potassium nitrite, [tex]\( \text{KNO}_2 \)[/tex]) and a strong acid (sulfuric acid, [tex]\( \text{H}_2\text{SO}_4 \)[/tex]), we can write both the reactants and the products. The products of this reaction are potassium sulfate ([tex]\( \text{K}_2\text{SO}_4 \)[/tex]) and nitrous acid ([tex]\( \text{HNO}_2 \)[/tex]).
Starting with the unbalanced equation:
[tex]\[ \text{KNO}_2 (aq) + \text{H}_2\text{SO}_4 (aq) \rightarrow \text{K}_2\text{SO}_4 (aq) + \text{HNO}_2 (aq) \][/tex]
Let us ensure that there are equal numbers of each type of atom on both sides of the equation:
- Potassium (K): On the left, we have 1 atom from [tex]\( \text{KNO}_2 \)[/tex]. On the right, [tex]\( \text{K}_2\text{SO}_4 \)[/tex] provides 2 potassium atoms, so we need 2 [tex]\( \text{KNO}_2 \)[/tex] molecules on the left.
- Nitrogen (N): By adjusting the potassium, we now have 2 nitrogen atoms from 2 [tex]\( \text{KNO}_2 \)[/tex] molecules on the left. On the right, each [tex]\( \text{HNO}_2 \)[/tex] provides 1 nitrogen atom. Thus, we need 2 [tex]\( \text{HNO}_2 \)[/tex] molecules on the right.
- Sulfur (S): The sulfur content from [tex]\( \text{H}_2\text{SO}_4 \)[/tex] and [tex]\( \text{K}_2\text{SO}_4 \)[/tex] is already balanced with 1 sulfur atom on each side.
- Oxygen (O): On the left, we have 2 oxygen atoms from each [tex]\( \text{KNO}_2 \)[/tex] (total 4) plus 4 from [tex]\( \text{H}_2\text{SO}_4 \)[/tex] (total 8). On the right, [tex]\( \text{K}_2\text{SO}_4 \)[/tex] has 4 oxygen atoms, and each [tex]\( \text{HNO}_2 \)[/tex] has 2 (total 4), summing up to 8, which is balanced.
- Hydrogen (H): On the left, 2 hydrogen atoms from [tex]\( \text{H}_2\text{SO}_4 \)[/tex]. On the right, we have 2 molecules of [tex]\( \text{HNO}_2 \)[/tex], each contributing 1 hydrogen atom (total 4), which is balanced.
Following these corrections, the fully balanced equation is:
[tex]\[ 2 \text{KNO}_2 (aq) + \text{H}_2\text{SO}_4 (aq) \rightarrow \text{K}_2\text{SO}_4 (aq) + 2 \text{HNO}_2 (aq) \][/tex]
This balanced equation reflects the reaction's stoichiometry, ensuring every atom is accounted for and conserved.
Starting with the unbalanced equation:
[tex]\[ \text{KNO}_2 (aq) + \text{H}_2\text{SO}_4 (aq) \rightarrow \text{K}_2\text{SO}_4 (aq) + \text{HNO}_2 (aq) \][/tex]
Let us ensure that there are equal numbers of each type of atom on both sides of the equation:
- Potassium (K): On the left, we have 1 atom from [tex]\( \text{KNO}_2 \)[/tex]. On the right, [tex]\( \text{K}_2\text{SO}_4 \)[/tex] provides 2 potassium atoms, so we need 2 [tex]\( \text{KNO}_2 \)[/tex] molecules on the left.
- Nitrogen (N): By adjusting the potassium, we now have 2 nitrogen atoms from 2 [tex]\( \text{KNO}_2 \)[/tex] molecules on the left. On the right, each [tex]\( \text{HNO}_2 \)[/tex] provides 1 nitrogen atom. Thus, we need 2 [tex]\( \text{HNO}_2 \)[/tex] molecules on the right.
- Sulfur (S): The sulfur content from [tex]\( \text{H}_2\text{SO}_4 \)[/tex] and [tex]\( \text{K}_2\text{SO}_4 \)[/tex] is already balanced with 1 sulfur atom on each side.
- Oxygen (O): On the left, we have 2 oxygen atoms from each [tex]\( \text{KNO}_2 \)[/tex] (total 4) plus 4 from [tex]\( \text{H}_2\text{SO}_4 \)[/tex] (total 8). On the right, [tex]\( \text{K}_2\text{SO}_4 \)[/tex] has 4 oxygen atoms, and each [tex]\( \text{HNO}_2 \)[/tex] has 2 (total 4), summing up to 8, which is balanced.
- Hydrogen (H): On the left, 2 hydrogen atoms from [tex]\( \text{H}_2\text{SO}_4 \)[/tex]. On the right, we have 2 molecules of [tex]\( \text{HNO}_2 \)[/tex], each contributing 1 hydrogen atom (total 4), which is balanced.
Following these corrections, the fully balanced equation is:
[tex]\[ 2 \text{KNO}_2 (aq) + \text{H}_2\text{SO}_4 (aq) \rightarrow \text{K}_2\text{SO}_4 (aq) + 2 \text{HNO}_2 (aq) \][/tex]
This balanced equation reflects the reaction's stoichiometry, ensuring every atom is accounted for and conserved.
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.