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What is the sum of the measures of the interior angles of a 12-gon?

A. [tex]$1620^{\circ}$[/tex]
B. [tex]$1800^{\circ}$[/tex]
C. [tex]$1980^{\circ}$[/tex]
D. [tex]$2160^{\circ}$[/tex]


Sagot :

To find the sum of the measures of the interior angles of a polygon, you can use the following formula for an [tex]\( n \)[/tex]-sided polygon (or [tex]\( n \)[/tex]-gon):

[tex]\[ \text{Sum of the interior angles} = (n - 2) \times 180^{\circ} \][/tex]

where [tex]\( n \)[/tex] is the number of sides of the polygon.

Let's use this formula to find the sum of the interior angles for a 12-sided polygon (12-gon):

1. Determine the number of sides, [tex]\( n \)[/tex], which is 12 in this case.
2. Substitute [tex]\( n = 12 \)[/tex] into the formula:

[tex]\[ \text{Sum of the interior angles} = (12 - 2) \times 180^{\circ} \][/tex]

3. Simplify the expression inside the parentheses:

[tex]\[ (12 - 2) = 10 \][/tex]

4. Multiply by 180 degrees:

[tex]\[ 10 \times 180^{\circ} = 1800^{\circ} \][/tex]

Therefore, the sum of the measures of the interior angles of a 12-gon is [tex]\( 1800^{\circ} \)[/tex].

The correct answer is [tex]\( 1800^{\circ} \)[/tex].