IDNLearn.com offers a user-friendly platform for finding and sharing answers. Join our knowledgeable community and get detailed, reliable answers to all your questions.
Sagot :
Alpha decay is a type of radioactive decay in which an unstable atomic nucleus ejects an alpha particle (which is essentially a helium-4 nucleus, [tex]\( {}_2^4 \text{He} \)[/tex]). In alpha decay, the parent nucleus loses 2 protons and 2 neutrons, resulting in a daughter nucleus with a mass number decreased by 4 and an atomic number decreased by 2.
Given this behavior of alpha decay, we need to identify which equation correctly represents this process:
1. [tex]\({ }_{95}^{241} \text{Am} \rightarrow { }_{93}^{237} \text{Np} + { }_{2}^{4} \text{He}\)[/tex]
2. [tex]\({ }_{9}^{18} \text{F} \rightarrow { }_{8}^{18} \text{O} + { }_{1}^{0} \text{e}\)[/tex]
3. [tex]\({ }_{6}^{14} \text{C} \rightarrow { }_{7}^{14} \text{N} + { }_{-1}^{0} \text{e}\)[/tex]
4. [tex]\({ }_{66}^{152} \text{Dy} \rightarrow { }_{66}^{152} \text{Dy} + y\)[/tex]
Let's analyze each equation step-by-step to determine which one represents alpha decay:
1. [tex]\({ }_{95}^{241} \text{Am} \rightarrow { }_{93}^{237} \text{Np} + { }_{2}^{4} \text{He}\)[/tex]:
- The element Americium-241 ([tex]\( {}_{95}^{241} \text{Am} \)[/tex]) decays to Neptunium-237 ([tex]\( {}_{93}^{237} \text{Np} \)[/tex]) and an alpha particle ([tex]\( {}_{2}^{4} \text{He} \)[/tex]).
- The atomic number decreases by 2 (from 95 to 93) and the mass number decreases by 4 (from 241 to 237).
- This correctly represents alpha decay.
2. [tex]\({ }_{9}^{18} \text{F} \rightarrow { }_{8}^{18} \text{O} + { }_{1}^{0} \text{e}\)[/tex]:
- The element Fluorine-18 ([tex]\( {}_{9}^{18} \text{F} \)[/tex]) decays to Oxygen-18 ([tex]\( {}_{8}^{18} \text{O} \)[/tex]) and a positron ([tex]\( {}_{1}^{0} \text{e} \)[/tex]).
- This represents beta-plus decay, not alpha decay.
3. [tex]\({ }_{6}^{14} \text{C} \rightarrow { }_{7}^{14} \text{N} + { }_{-1}^{0} \text{e}\)[/tex]:
- The element Carbon-14 ([tex]\( {}_{6}^{14} \text{C} \)[/tex]) decays to Nitrogen-14 ([tex]\( {}_{7}^{14} \text{N} \)[/tex]) and an electron ([tex]\( {}_{-1}^{0} \text{e} \)[/tex]).
- This represents beta-minus decay, not alpha decay.
4. [tex]\({ }_{66}^{152} \text{Dy} \rightarrow { }_{66}^{152} \text{Dy} + y\)[/tex]:
- Dysprosium-152 ([tex]\( {}_{66}^{152} \text{Dy} \)[/tex]) supposedly decays to itself ([tex]\( {}_{66}^{152} \text{Dy} \)[/tex]) and some unspecified particle [tex]\(y\)[/tex].
- This does not represent any standard decay process.
Therefore, the correct equation that represents alpha decay is:
[tex]\({ }_{95}^{241} \text{Am} \rightarrow { }_{93}^{237} \text{Np} + { }_{2}^{4} \text{He}\)[/tex]
Given this behavior of alpha decay, we need to identify which equation correctly represents this process:
1. [tex]\({ }_{95}^{241} \text{Am} \rightarrow { }_{93}^{237} \text{Np} + { }_{2}^{4} \text{He}\)[/tex]
2. [tex]\({ }_{9}^{18} \text{F} \rightarrow { }_{8}^{18} \text{O} + { }_{1}^{0} \text{e}\)[/tex]
3. [tex]\({ }_{6}^{14} \text{C} \rightarrow { }_{7}^{14} \text{N} + { }_{-1}^{0} \text{e}\)[/tex]
4. [tex]\({ }_{66}^{152} \text{Dy} \rightarrow { }_{66}^{152} \text{Dy} + y\)[/tex]
Let's analyze each equation step-by-step to determine which one represents alpha decay:
1. [tex]\({ }_{95}^{241} \text{Am} \rightarrow { }_{93}^{237} \text{Np} + { }_{2}^{4} \text{He}\)[/tex]:
- The element Americium-241 ([tex]\( {}_{95}^{241} \text{Am} \)[/tex]) decays to Neptunium-237 ([tex]\( {}_{93}^{237} \text{Np} \)[/tex]) and an alpha particle ([tex]\( {}_{2}^{4} \text{He} \)[/tex]).
- The atomic number decreases by 2 (from 95 to 93) and the mass number decreases by 4 (from 241 to 237).
- This correctly represents alpha decay.
2. [tex]\({ }_{9}^{18} \text{F} \rightarrow { }_{8}^{18} \text{O} + { }_{1}^{0} \text{e}\)[/tex]:
- The element Fluorine-18 ([tex]\( {}_{9}^{18} \text{F} \)[/tex]) decays to Oxygen-18 ([tex]\( {}_{8}^{18} \text{O} \)[/tex]) and a positron ([tex]\( {}_{1}^{0} \text{e} \)[/tex]).
- This represents beta-plus decay, not alpha decay.
3. [tex]\({ }_{6}^{14} \text{C} \rightarrow { }_{7}^{14} \text{N} + { }_{-1}^{0} \text{e}\)[/tex]:
- The element Carbon-14 ([tex]\( {}_{6}^{14} \text{C} \)[/tex]) decays to Nitrogen-14 ([tex]\( {}_{7}^{14} \text{N} \)[/tex]) and an electron ([tex]\( {}_{-1}^{0} \text{e} \)[/tex]).
- This represents beta-minus decay, not alpha decay.
4. [tex]\({ }_{66}^{152} \text{Dy} \rightarrow { }_{66}^{152} \text{Dy} + y\)[/tex]:
- Dysprosium-152 ([tex]\( {}_{66}^{152} \text{Dy} \)[/tex]) supposedly decays to itself ([tex]\( {}_{66}^{152} \text{Dy} \)[/tex]) and some unspecified particle [tex]\(y\)[/tex].
- This does not represent any standard decay process.
Therefore, the correct equation that represents alpha decay is:
[tex]\({ }_{95}^{241} \text{Am} \rightarrow { }_{93}^{237} \text{Np} + { }_{2}^{4} \text{He}\)[/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.