Get comprehensive answers to your questions with the help of IDNLearn.com's community. Join our community to receive prompt and reliable responses to your questions from experienced professionals.

Drag each tile to the correct box. Not all tiles will be used.

Consider the function [tex]f(x)=\sqrt{7x-21}[/tex].

Place the steps for finding [tex]f^{-1}(x)[/tex] in the correct order.

[tex]
\begin{array}{c}
1. x=\sqrt{7y-21} \\
2. x^2=7y-21 \\
3. x^2+21=7y \\
4. \frac{1}{7}\left(x^2-21\right)=f^{-1}(x), \text{ where } x \geq 0 \\
\hline
\end{array}
[/tex]


Sagot :

To determine the steps for finding the inverse of the function [tex]\( f(x) = \sqrt{7x - 21} \)[/tex], we can arrange the following steps in the correct order:

1. Start with [tex]\( x = \sqrt{7y - 21} \)[/tex]
2. Square both sides to remove the square root:
[tex]\[ x^2 = 7y - 21 \][/tex]
3. Add 21 to both sides to isolate the [tex]\( y \)[/tex]-term:
[tex]\[ x^2 + 21 = 7y \][/tex]
4. Solve for [tex]\( y \)[/tex] by dividing both sides by 7:
[tex]\[ y = \frac{1}{7} (x^2 + 21), \text{ where } x \geq 0 \][/tex]

Arranging the given steps, the correct order is:

1. [tex]\( x = \sqrt{7y - 21} \)[/tex]
2. [tex]\( x^2 = 7y - 21 \)[/tex]
3. [tex]\( x^2 + 21 = 7y \)[/tex]
4. [tex]\( \frac{1}{7}(x^2 + 21) = f^{-1}(x), \text{ where } x \geq 0 \)[/tex]

So, the steps in order should be:

1. [tex]\( x = \sqrt{7 y - 21} \)[/tex]
2. [tex]\( x^2 = 7 y - 21 \)[/tex]
3. [tex]\( x^2 + 21 = 7 y \)[/tex]
4. [tex]\( \frac{1}{7}(x^2 + 21) = f^{-1}(x), \text { where } x \geq 0 \)[/tex]