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Solve the first equation in the system for [tex]y[/tex].

[tex]
\left\{
\begin{array}{l}
2x + y = 1 \\
3x + 2y = 0
\end{array}
\right.
[/tex]

Enter the expression in the box.

[tex]
y = \square
[/tex]

Sagot :

GinnyAnsweridn
To solve the first equation in the system for [tex]\( y \)[/tex], follow these steps:

1. Write down the first equation:
[tex]\[ 2x + y = 1 \][/tex]

2. Isolate [tex]\( y \)[/tex] on one side of the equation. To do this, subtract [tex]\( 2x \)[/tex] from both sides:
[tex]\[ y = 1 - 2x \][/tex]

Therefore, the expression for [tex]\( y \)[/tex] in terms of [tex]\( x \)[/tex] is:
[tex]\[ y = 1 - 2x \][/tex]
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