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Find the quotient of [tex]40 \div 7[/tex].

A. [tex]7 \times 5[/tex]
B. [tex]6 \, r \, 1[/tex]
C. [tex]5.5[/tex]
D. [tex]5.3[/tex]


Sagot :

Sure, let's address each part of the question one step at a time:

1. Finding the quotient of [tex]\( 40 \div 7 \)[/tex]:

To find the quotient of [tex]\( 40 \div 7 \)[/tex], you simply divide 40 by 7, which gives us a more precise decimal:

[tex]\[ \frac{40}{7} = 5.714285714285714 \][/tex]

So, the quotient is approximately [tex]\( 5.714285714285714 \)[/tex].

2. Calculating [tex]\( 7 \times 5 \)[/tex]:

Multiplying 7 by 5 is straightforward:

[tex]\[ 7 \times 5 = 35 \][/tex]

So, the product is [tex]\( 35 \)[/tex].

3. Interpreting [tex]\( 6 \text{ r } 1 \)[/tex] (usually written [tex]\( 6 \operatorname{mod} 1 \)[/tex]):

This part does not directly align with what you are looking for, but assuming you intended to find the quotient and remainder of [tex]\( 40 \div 7 \)[/tex], let’s write it correctly:

When you divide 40 by 7, the integer division gives:

[tex]\[ 40 \div 7 = 5 \quad \text{(quotient)} \][/tex]

The remainder is:

[tex]\[ 40 \mod 7 = 5 \quad \text{(remainder)} \][/tex]

Therefore, [tex]\( 40 \div 7 \)[/tex] provides a quotient of 5 with a remainder of 5.

4. Given the number 5.5:

If this number is taken into account for the quotient of [tex]\( 40 \div 7 \)[/tex], as elucidated earlier, [tex]\( 40 \div 7 \)[/tex] exactly gives [tex]\( 5.714285714285714 \)[/tex], not [tex]\( 5.5 \)[/tex].

5. Sample tuple [tex]\( (5, 3) \)[/tex]:

This part seems extraneous and not related to the current set of calculations. Assuming it’s an additional piece of information, we'll only recognize that it doesn’t play a role in the calculations above, and should be omitted from consideration.

Summarizing all parts:

1. The quotient of [tex]\( 40 \div 7 \)[/tex] is [tex]\( 5.714285714285714 \)[/tex].
2. The product of [tex]\( 7 \times 5 \)[/tex] is [tex]\( 35 \)[/tex].
3. [tex]\( 40 \div 7 \)[/tex] gives a quotient of 5 with a remainder of 5 (interpreting [tex]\( 6r1 \)[/tex] correctly).