Discover a world of knowledge and get your questions answered at IDNLearn.com. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

Combine like terms in the given polynomial. Then, evaluate for [tex] x = 3, y = -1 [/tex].

[tex]\[ x y + 3 x y^2 - 2 x y + 3 x^2 y - 2 x y^2 + x y \][/tex]

A. [tex]\[ 4 x y + x y^2 + 3 x^2 y \quad ; \quad -36 \][/tex]

B. [tex]\[ 3 x^2 y + x y^2 \quad ; \quad -30 \][/tex]

C. [tex]\[ x y^2 + 3 x^2 y \quad ; \quad -24 \][/tex]

D. [tex]\[ 8 x^2 y^2 + 4 x y \quad ; \quad 60 \][/tex]


Sagot :

Sure, let's combine the like terms in the given polynomial and then evaluate it for [tex]\( x = 3 \)[/tex] and [tex]\( y = -1 \)[/tex].

The polynomial given is:
[tex]\[ x y + 3 x y^2 - 2 x y + 3 x^2 y - 2 x y^2 + x y \][/tex]

First, let's identify and group the like terms:
- Terms containing [tex]\( xy \)[/tex]: [tex]\( x y, -2 x y, x y \)[/tex]
- Terms containing [tex]\( xy^2 \)[/tex]: [tex]\( 3 x y^2, -2 x y^2 \)[/tex]
- Terms containing [tex]\( x^2y \)[/tex]: [tex]\( 3 x^2 y \)[/tex]

Now, let's combine these like terms:
1. For the [tex]\( xy \)[/tex] terms:
[tex]\[ x y - 2 x y + x y = (1 - 2 + 1) x y = 0 x y \][/tex]

2. For the [tex]\( xy^2 \)[/tex] terms:
[tex]\[ 3 x y^2 - 2 x y^2 = (3 - 2) x y^2 = 1 x y^2 \][/tex]

3. For the [tex]\( x^2y \)[/tex] term:
[tex]\[ 3 x^2 y \][/tex]

So, combining all like terms, we have:
[tex]\[ 0 x y + x y^2 + 3 x^2 y = x y^2 + 3 x^2 y \][/tex]

Now we need to evaluate this simplified polynomial at [tex]\( x = 3 \)[/tex] and [tex]\( y = -1 \)[/tex]:
[tex]\[ x y^2 + 3 x^2 y \][/tex]

Substitute [tex]\( x = 3 \)[/tex] and [tex]\( y = -1 \)[/tex]:
[tex]\[ 3(-1)^2 + 3(3)^2(-1) \][/tex]

Calculate the value step-by-step:
1. Evaluate [tex]\( (-1)^2 = 1 \)[/tex],
[tex]\[ 3(1) + 3(3)^2(-1) \][/tex]
2. Evaluate [tex]\( (3)^2 = 9 \)[/tex],
[tex]\[ 3(1) + 3(9)(-1) \][/tex]
3. Then,
[tex]\[ 3 + 3(9)(-1) = 3 + 3*(-9) \][/tex]
4. Finally,
[tex]\[ 3 + (-27) = -24 \][/tex]

Thus, the simplified polynomial is [tex]\( x y^2 + 3 x^2 y \)[/tex], and its value when [tex]\( x = 3 \)[/tex] and [tex]\( y = -1 \)[/tex] is [tex]\(-24\)[/tex].

So, the correct option in your list is:
[tex]\[ x y^2 + 3 x^2 y ;-24 \][/tex]