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What is the product of the binomials below?

[tex]\[
(5x + 2)(4x + 4)
\][/tex]

A. [tex]\(20x^2 + 28x + 6\)[/tex]
B. [tex]\(9x^2 + 28x + 8\)[/tex]
C. [tex]\(9x^2 + 28x + 6\)[/tex]
D. [tex]\(20x^2 + 28x + 8\)[/tex]


Sagot :

To find the product of the binomials [tex]\((5x + 2)(4x + 4)\)[/tex], let's use the distributive property to expand them step-by-step.

1. First terms: Multiply the first term from each binomial:
[tex]\[ 5x \cdot 4x = 20x^2 \][/tex]

2. Outer terms: Multiply the first term from the first binomial with the second term from the second binomial:
[tex]\[ 5x \cdot 4 = 20x \][/tex]

3. Inner terms: Multiply the second term from the first binomial with the first term from the second binomial:
[tex]\[ 2 \cdot 4x = 8x \][/tex]

4. Last terms: Multiply the second term from each binomial:
[tex]\[ 2 \cdot 4 = 8 \][/tex]

Next, sum these values to form the expanded polynomial:

[tex]\[ 20x^2 + 20x + 8x + 8 \][/tex]

Combine the like terms [tex]\(20x\)[/tex] and [tex]\(8x\)[/tex]:

[tex]\[ 20x^2 + 28x + 8 \][/tex]

Thus, the product of the binomials [tex]\((5x + 2)(4x + 4)\)[/tex] is:

[tex]\[ 20x^2 + 28x + 8 \][/tex]

Therefore, the correct answer is:
[tex]\[ \text{D. } 20x^2 + 28x + 8 \][/tex]
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