IDNLearn.com is your reliable source for expert answers and community insights. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.

This table represents values of a cubic polynomial function.
\begin{tabular}{|c|c|}
\hline
[tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline
-2 & -12 \\
\hline
-1 & 0 \\
\hline
0 & 6 \\
\hline
1 & 7.5 \\
\hline
2 & 6 \\
\hline
3 & 3 \\
\hline
\end{tabular}

Based on the information in the table, which sentence best describes the interval [tex]$[-2,1]$[/tex]?

A. The function is both increasing and decreasing on the interval [tex]$[-2,1]$[/tex].

B. The function is constant on the interval [tex]$[-2,1]$[/tex].

C. The function is decreasing on the interval [tex]$[-2,1]$[/tex].

D. The function is increasing on the interval [tex]$[-2,1]$[/tex].


Sagot :

Let's analyze the given values of the function on the interval [tex]\([-2, 1]\)[/tex]:

[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -2 & -12 \\ \hline -1 & 0 \\ \hline 0 & 6 \\ \hline 1 & 7.5 \\ \hline \end{array} \][/tex]

We will look at how the [tex]\( y \)[/tex]-values change as [tex]\( x \)[/tex] increases from [tex]\(-2\)[/tex] to [tex]\(1\)[/tex]:

1. From [tex]\(-2\)[/tex] to [tex]\(-1\)[/tex]:
- When [tex]\( x = -2 \)[/tex], [tex]\( y = -12 \)[/tex]
- When [tex]\( x = -1 \)[/tex], [tex]\( y = 0 \)[/tex]
- The function value increases from [tex]\(-12\)[/tex] to [tex]\(0\)[/tex].

2. From [tex]\(-1\)[/tex] to [tex]\(0\)[/tex]:
- When [tex]\( x = -1 \)[/tex], [tex]\( y = 0 \)[/tex]
- When [tex]\( x = 0 \)[/tex], [tex]\( y = 6 \)[/tex]
- The function value increases from [tex]\(0\)[/tex] to [tex]\(6\)[/tex].

3. From [tex]\(0\)[/tex] to [tex]\(1\)[/tex]:
- When [tex]\( x = 0 \)[/tex], [tex]\( y = 6 \)[/tex]
- When [tex]\( x = 1 \)[/tex], [tex]\( y = 7.5 \)[/tex]
- The function value increases from [tex]\(6\)[/tex] to [tex]\(7.5\)[/tex].

In each of these intervals, the [tex]\( y \)[/tex]-value increases as the [tex]\( x \)[/tex]-value increases. Thus, the function is consistently increasing throughout the entire interval [tex]\([-2, 1]\)[/tex].

Therefore, the sentence that best describes the interval [tex]\([-2, 1]\)[/tex] is:

D. The function is increasing on the interval [tex]\([-2, 1]\)[/tex].