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Sagot :
To determine the probability of having exactly 2 defective parts in a day, you need to refer to the provided probability distribution table. The table lists the number of defective parts [tex]\( X \)[/tex] and their corresponding probabilities [tex]\( P(X) \)[/tex].
Here's the table for reference:
[tex]\[ \begin{tabular}{|c|c|} \hline \text{Defective Parts: } X & \text{Probability: } P(X) \\ \hline 0 & 0.85 \\ \hline 1 & 0.10 \\ \hline 2 & 0.04 \\ \hline 3 & 0.01 \\ \hline \end{tabular} \][/tex]
To find the probability that Shelia encounters exactly 2 defective parts on a given day:
1. Identify the row in the table where [tex]\( X = 2 \)[/tex].
2. Look at the corresponding probability value [tex]\( P(X = 2) \)[/tex].
From the table:
[tex]\[ P(X = 2) = 0.04 \][/tex]
Therefore, the probability of having 2 defective parts in a day is:
[tex]\[ \boxed{0.04} \][/tex]
Here's the table for reference:
[tex]\[ \begin{tabular}{|c|c|} \hline \text{Defective Parts: } X & \text{Probability: } P(X) \\ \hline 0 & 0.85 \\ \hline 1 & 0.10 \\ \hline 2 & 0.04 \\ \hline 3 & 0.01 \\ \hline \end{tabular} \][/tex]
To find the probability that Shelia encounters exactly 2 defective parts on a given day:
1. Identify the row in the table where [tex]\( X = 2 \)[/tex].
2. Look at the corresponding probability value [tex]\( P(X = 2) \)[/tex].
From the table:
[tex]\[ P(X = 2) = 0.04 \][/tex]
Therefore, the probability of having 2 defective parts in a day is:
[tex]\[ \boxed{0.04} \][/tex]
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