Connect with a global community of knowledgeable individuals on IDNLearn.com. Get the information you need from our community of experts who provide accurate and thorough answers to all your questions.
Sagot :
Let's walk through the problem step-by-step to understand where Heather might have gone wrong.
We are given two points:
- Point [tex]\( R(-3, -4) \)[/tex]
- Point [tex]\( S(5, 7) \)[/tex]
The formula to calculate the distance between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
1. Calculate the Differences:
[tex]\[ \Delta x = x_2 - x_1 = 5 - (-3) = 5 + 3 = 8 \][/tex]
[tex]\[ \Delta y = y_2 - y_1 = 7 - (-4) = 7 + 4 = 11 \][/tex]
2. Square the Differences:
[tex]\[ (\Delta x)^2 = 8^2 = 64 \][/tex]
[tex]\[ (\Delta y)^2 = 11^2 = 121 \][/tex]
3. Add the Squares:
[tex]\[ \text{Sum of squares} = 64 + 121 = 185 \][/tex]
4. Calculate the Distance:
[tex]\[ d = \sqrt{185} \approx 13.60 \][/tex]
Now, let's analyze Heather's calculations:
[tex]\[ RS = \sqrt{((-4)-(-3))^2 + (7-5)^2} \][/tex]
[tex]\[ RS = \sqrt{(-1)^2 + (2)^2} \][/tex]
[tex]\[ RS = \sqrt{1 + 4} \][/tex]
[tex]\[ RS = \sqrt{5} \][/tex]
Heather's Calculation:
[tex]\[ RS = \sqrt{5} \approx 2.236 \][/tex]
Compare Heather's calculation with the correct calculation.
Heather substituted [tex]\((x_2, y_1)\)[/tex] and [tex]\((y_2 - y_1)\)[/tex] as follows:
[tex]\[ \Delta x = -4 - (-3) = -1 \][/tex]
[tex]\[ \Delta y = 7 - 5 = 2 \][/tex]
While the correct differences should be:
[tex]\[ x_2 - x_1 = 5 - (-3) = 8 \][/tex]
[tex]\[ y_2 - y_1 = 7 - (-4) = 11 \][/tex]
When Heather calculated the distance, she used the wrong differences. Therefore, the error lies in how she substituted the coordinates into the distance formula.
Thus, the correct answer is:
A. She substituted incorrectly into the distance formula.
We are given two points:
- Point [tex]\( R(-3, -4) \)[/tex]
- Point [tex]\( S(5, 7) \)[/tex]
The formula to calculate the distance between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
1. Calculate the Differences:
[tex]\[ \Delta x = x_2 - x_1 = 5 - (-3) = 5 + 3 = 8 \][/tex]
[tex]\[ \Delta y = y_2 - y_1 = 7 - (-4) = 7 + 4 = 11 \][/tex]
2. Square the Differences:
[tex]\[ (\Delta x)^2 = 8^2 = 64 \][/tex]
[tex]\[ (\Delta y)^2 = 11^2 = 121 \][/tex]
3. Add the Squares:
[tex]\[ \text{Sum of squares} = 64 + 121 = 185 \][/tex]
4. Calculate the Distance:
[tex]\[ d = \sqrt{185} \approx 13.60 \][/tex]
Now, let's analyze Heather's calculations:
[tex]\[ RS = \sqrt{((-4)-(-3))^2 + (7-5)^2} \][/tex]
[tex]\[ RS = \sqrt{(-1)^2 + (2)^2} \][/tex]
[tex]\[ RS = \sqrt{1 + 4} \][/tex]
[tex]\[ RS = \sqrt{5} \][/tex]
Heather's Calculation:
[tex]\[ RS = \sqrt{5} \approx 2.236 \][/tex]
Compare Heather's calculation with the correct calculation.
Heather substituted [tex]\((x_2, y_1)\)[/tex] and [tex]\((y_2 - y_1)\)[/tex] as follows:
[tex]\[ \Delta x = -4 - (-3) = -1 \][/tex]
[tex]\[ \Delta y = 7 - 5 = 2 \][/tex]
While the correct differences should be:
[tex]\[ x_2 - x_1 = 5 - (-3) = 8 \][/tex]
[tex]\[ y_2 - y_1 = 7 - (-4) = 11 \][/tex]
When Heather calculated the distance, she used the wrong differences. Therefore, the error lies in how she substituted the coordinates into the distance formula.
Thus, the correct answer is:
A. She substituted incorrectly into the distance formula.
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.