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Sagot :
To determine the concentration of hydroxide ions ([tex]\(OH^-\)[/tex]) in a solution given its pOH, we use the formula:
[tex]\[ [OH^{-}] = 10^{- \text{pOH}} \][/tex]
Let's go through the steps to solve this problem:
1. You are given the pOH of the solution as 10.75.
2. Using the formula, [tex]\([OH^{-}] = 10^{- \text{pOH}}\)[/tex], we substitute the given pOH value into the equation:
[tex]\[ [OH^{-}] = 10^{-10.75} \][/tex]
3. Evaluating this expression results in a numerical value for the concentration of [tex]\(OH^{-}\)[/tex] ions:
[tex]\[ [OH^{-}] = 1.778 \times 10^{-11} \text{ M} \][/tex]
Therefore, the concentration of [tex]\(OH^{-}\)[/tex] ions in the solution is [tex]\(1.778 \times 10^{-11} \text{ M}\)[/tex].
Among the given options, the correct answer is:
[tex]\[ 1.778 \times 10^{-11} \text{ M} \][/tex]
[tex]\[ [OH^{-}] = 10^{- \text{pOH}} \][/tex]
Let's go through the steps to solve this problem:
1. You are given the pOH of the solution as 10.75.
2. Using the formula, [tex]\([OH^{-}] = 10^{- \text{pOH}}\)[/tex], we substitute the given pOH value into the equation:
[tex]\[ [OH^{-}] = 10^{-10.75} \][/tex]
3. Evaluating this expression results in a numerical value for the concentration of [tex]\(OH^{-}\)[/tex] ions:
[tex]\[ [OH^{-}] = 1.778 \times 10^{-11} \text{ M} \][/tex]
Therefore, the concentration of [tex]\(OH^{-}\)[/tex] ions in the solution is [tex]\(1.778 \times 10^{-11} \text{ M}\)[/tex].
Among the given options, the correct answer is:
[tex]\[ 1.778 \times 10^{-11} \text{ M} \][/tex]
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