Join the IDNLearn.com community and start exploring a world of knowledge today. Our experts provide timely, comprehensive responses to ensure you have the information you need.
Sagot :
To evaluate the function [tex]\( y = \ln (x-2) \)[/tex] for given values of [tex]\( x \)[/tex], we follow these steps:
1. Substitute each [tex]\( x \)[/tex] value into the function [tex]\( y = \ln (x-2) \)[/tex].
2. Compute the natural logarithm (ln) of the resulting value.
3. Round the result to the nearest thousandth.
Let's do this for each given value of [tex]\( x \)[/tex]:
1. When [tex]\( x = 3 \)[/tex]:
[tex]\[ y = \ln (3 - 2) = \ln 1 = 0.0 \][/tex]
Therefore, [tex]\( y = 0.0 \)[/tex].
2. When [tex]\( x = 4 \)[/tex]:
[tex]\[ y = \ln (4 - 2) = \ln 2 \approx 0.693 \][/tex]
Therefore, [tex]\( y \approx 0.693 \)[/tex].
3. When [tex]\( x = 6 \)[/tex]:
[tex]\[ y = \ln (6 - 2) = \ln 4 \approx 1.386 \][/tex]
Therefore, [tex]\( y \approx 1.386 \)[/tex].
So, the values are:
For [tex]\( x = 3 \)[/tex], [tex]\( y = 0.0 \)[/tex].
For [tex]\( x = 4 \)[/tex], [tex]\( y \approx 0.693 \)[/tex].
For [tex]\( x = 6 \)[/tex], [tex]\( y \approx 1.386 \)[/tex].
1. Substitute each [tex]\( x \)[/tex] value into the function [tex]\( y = \ln (x-2) \)[/tex].
2. Compute the natural logarithm (ln) of the resulting value.
3. Round the result to the nearest thousandth.
Let's do this for each given value of [tex]\( x \)[/tex]:
1. When [tex]\( x = 3 \)[/tex]:
[tex]\[ y = \ln (3 - 2) = \ln 1 = 0.0 \][/tex]
Therefore, [tex]\( y = 0.0 \)[/tex].
2. When [tex]\( x = 4 \)[/tex]:
[tex]\[ y = \ln (4 - 2) = \ln 2 \approx 0.693 \][/tex]
Therefore, [tex]\( y \approx 0.693 \)[/tex].
3. When [tex]\( x = 6 \)[/tex]:
[tex]\[ y = \ln (6 - 2) = \ln 4 \approx 1.386 \][/tex]
Therefore, [tex]\( y \approx 1.386 \)[/tex].
So, the values are:
For [tex]\( x = 3 \)[/tex], [tex]\( y = 0.0 \)[/tex].
For [tex]\( x = 4 \)[/tex], [tex]\( y \approx 0.693 \)[/tex].
For [tex]\( x = 6 \)[/tex], [tex]\( y \approx 1.386 \)[/tex].
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.