IDNLearn.com makes it easy to find accurate answers to your questions. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.
Sagot :
To determine the molarity of the given KCl solution, we need to follow these steps:
1. Find the moles of KCl:
First, we need to calculate the number of moles of KCl. We can do this by using the formula:
[tex]\[ \text{moles of KCl} = \frac{\text{mass of KCl}}{\text{molar mass of KCl}} \][/tex]
Given data:
- Mass of KCl = 8.45 g
- Molar mass of KCl = 74.55 g/mol
Substituting the values:
[tex]\[ \text{moles of KCl} = \frac{8.45 \text{ g}}{74.55 \text{ g/mol}} \approx 0.113 \][/tex]
So, the moles of KCl are approximately [tex]\(0.113 \text{ mol}\)[/tex].
2. Calculate the molarity of the solution:
The molarity (M) is calculated using the formula:
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]
Given data:
- Volume of the solution = 0.750 L
Substituting the values:
[tex]\[ \text{Molarity (M)} = \frac{0.113 \text{ mol}}{0.750 \text{ L}} \approx 0.151 \text{ M} \][/tex]
Therefore, the molarity of the solution is approximately [tex]\(0.151 \text{ M}\)[/tex].
From the provided options, the correct molarity is:
[tex]\[ \boxed{0.151 \text{ M}} \][/tex]
1. Find the moles of KCl:
First, we need to calculate the number of moles of KCl. We can do this by using the formula:
[tex]\[ \text{moles of KCl} = \frac{\text{mass of KCl}}{\text{molar mass of KCl}} \][/tex]
Given data:
- Mass of KCl = 8.45 g
- Molar mass of KCl = 74.55 g/mol
Substituting the values:
[tex]\[ \text{moles of KCl} = \frac{8.45 \text{ g}}{74.55 \text{ g/mol}} \approx 0.113 \][/tex]
So, the moles of KCl are approximately [tex]\(0.113 \text{ mol}\)[/tex].
2. Calculate the molarity of the solution:
The molarity (M) is calculated using the formula:
[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]
Given data:
- Volume of the solution = 0.750 L
Substituting the values:
[tex]\[ \text{Molarity (M)} = \frac{0.113 \text{ mol}}{0.750 \text{ L}} \approx 0.151 \text{ M} \][/tex]
Therefore, the molarity of the solution is approximately [tex]\(0.151 \text{ M}\)[/tex].
From the provided options, the correct molarity is:
[tex]\[ \boxed{0.151 \text{ M}} \][/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.