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The table below shows four samples of carbon dioxide and the temperature of the water that they were dissolved in.

\begin{tabular}{|c|c|}
\hline Sample & Temperature of water [tex]$\left({ }^{\circ} C \right)$[/tex] \\
\hline 1 & 78 \\
\hline 2 & 73 \\
\hline 3 & 55 \\
\hline 4 & 63 \\
\hline
\end{tabular}

Which of the samples most likely had the lowest solubility?

A. 1
B. 2
C. 3
D. 4

Sagot :

GinnyAnsweridn
To determine which sample most likely had the lowest solubility of carbon dioxide in water, we need to analyze the relationship between the temperature of the water and the solubility of gases. Generally, the solubility of gases in liquids decreases as the temperature increases. Hence, the higher the temperature, the lower the solubility of the gas.

Here, we have four samples with the following temperatures:
1. Sample 1: 78°C
2. Sample 2: 73°C
3. Sample 3: 55°C
4. Sample 4: 63°C

To find the sample with the lowest solubility, we should identify the sample with the highest temperature, because a higher temperature results in lower solubility for gases.

Comparing the temperatures of the four samples:
- Sample 1 has a temperature of 78°C.
- Sample 2 has a temperature of 73°C.
- Sample 3 has a temperature of 55°C.
- Sample 4 has a temperature of 63°C.

Among these temperatures, 78°C is the highest. Therefore, Sample 1, which is at 78°C, most likely had the lowest solubility.

So, the sample most likely had the lowest solubility is:

Sample 1.
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