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Sierra did 500 J of work to move her couch. If she exerts 250 N of force on the couch, how far did she move it?

(Work: [tex] W = Fd [/tex])

A. 0.5 m
B. 2 m
C. 250 m
D. 750 m


Sagot :

To determine how far Sierra moved the couch, we need to make use of the work-energy principle which relates work, force, and distance through the formula [tex]\( W = F \cdot d \)[/tex]. Here:

- [tex]\( W \)[/tex] is the work done, which is 500 joules (J).
- [tex]\( F \)[/tex] is the force applied, which is 250 newtons (N).
- [tex]\( d \)[/tex] is the distance, which we need to find.

Given the formula [tex]\( W = F \cdot d \)[/tex], we can rearrange it to solve for the distance [tex]\( d \)[/tex]:

[tex]\[ d = \frac{W}{F} \][/tex]

Substitute the given values into the formula:

[tex]\[ d = \frac{500 \text{ J}}{250 \text{ N}} \][/tex]

Now, perform the division:

[tex]\[ d = 2 \text{ meters} \][/tex]

Therefore, Sierra moved the couch 2 meters. The correct answer is:

2 m
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