IDNLearn.com: Where your questions are met with thoughtful and precise answers. Our Q&A platform offers detailed and trustworthy answers to ensure you have the information you need.
Sagot :
Let's solve the problem step by step:
### Step 1: Understand the problem
We have a square garden plot with an area of 75 square feet, and we need to determine:
a. The length of each side in simplest radical form.
b. The length of each side to the nearest tenth of a foot.
### Step 2: Setup and solve for the side length
Definition: The area [tex]\( A \)[/tex] of a square with side length [tex]\( s \)[/tex] is given by:
[tex]\[ A = s^2 \][/tex]
Given that [tex]\( A = 75 \)[/tex] square feet, we need to solve for [tex]\( s \)[/tex].
### Step 3: Find the side length in simplest radical form
To find the side length [tex]\( s \)[/tex] from the area:
[tex]\[ s = \sqrt{A} \][/tex]
[tex]\[ s = \sqrt{75} \][/tex]
Next, simplify [tex]\( \sqrt{75} \)[/tex]:
[tex]\[ 75 = 25 \times 3 \][/tex]
[tex]\[ \sqrt{75} = \sqrt{25 \times 3} \][/tex]
[tex]\[ \sqrt{75} = \sqrt{25} \times \sqrt{3} \][/tex]
[tex]\[ \sqrt{75} = 5 \sqrt{3} \][/tex]
So, the simplest radical form for the side length is [tex]\( 5 \sqrt{3} \)[/tex].
### Step 4: Find the side length to the nearest tenth of a foot
To find the decimal form of [tex]\( 5 \sqrt{3} \)[/tex]:
[tex]\[ 5 \sqrt{3} \approx 5 \times 1.732 \approx 8.66 \][/tex]
Rounding 8.66 to the nearest tenth, we get:
[tex]\[ 5 \sqrt{3} \approx 8.7 \][/tex]
### Step 5: Match the results with the given options
The results we have found are:
a. The simplest radical form: [tex]\( 5 \sqrt{3} \)[/tex]
b. The length to the nearest tenth: [tex]\( 8.7 \)[/tex] feet
Looking at the given options:
1. [tex]\( \frac{75}{4} ; 18.8 ft \)[/tex]
2. [tex]\( \sqrt{75} ; 9 ft \)[/tex]
3. [tex]\( \frac{\sqrt{75}}{2} ; 4.33 ft \)[/tex]
4. [tex]\( 5 \sqrt{3} ; 8.7 ft \)[/tex]
The correct pair that matches our findings is:
[tex]\[ 5 \sqrt{3} ; 8.7 ft \][/tex]
### Conclusion
Therefore, the correct answer to the problem is:
[tex]\[ 5 \sqrt{3} ; 8.7 ft \][/tex]
### Step 1: Understand the problem
We have a square garden plot with an area of 75 square feet, and we need to determine:
a. The length of each side in simplest radical form.
b. The length of each side to the nearest tenth of a foot.
### Step 2: Setup and solve for the side length
Definition: The area [tex]\( A \)[/tex] of a square with side length [tex]\( s \)[/tex] is given by:
[tex]\[ A = s^2 \][/tex]
Given that [tex]\( A = 75 \)[/tex] square feet, we need to solve for [tex]\( s \)[/tex].
### Step 3: Find the side length in simplest radical form
To find the side length [tex]\( s \)[/tex] from the area:
[tex]\[ s = \sqrt{A} \][/tex]
[tex]\[ s = \sqrt{75} \][/tex]
Next, simplify [tex]\( \sqrt{75} \)[/tex]:
[tex]\[ 75 = 25 \times 3 \][/tex]
[tex]\[ \sqrt{75} = \sqrt{25 \times 3} \][/tex]
[tex]\[ \sqrt{75} = \sqrt{25} \times \sqrt{3} \][/tex]
[tex]\[ \sqrt{75} = 5 \sqrt{3} \][/tex]
So, the simplest radical form for the side length is [tex]\( 5 \sqrt{3} \)[/tex].
### Step 4: Find the side length to the nearest tenth of a foot
To find the decimal form of [tex]\( 5 \sqrt{3} \)[/tex]:
[tex]\[ 5 \sqrt{3} \approx 5 \times 1.732 \approx 8.66 \][/tex]
Rounding 8.66 to the nearest tenth, we get:
[tex]\[ 5 \sqrt{3} \approx 8.7 \][/tex]
### Step 5: Match the results with the given options
The results we have found are:
a. The simplest radical form: [tex]\( 5 \sqrt{3} \)[/tex]
b. The length to the nearest tenth: [tex]\( 8.7 \)[/tex] feet
Looking at the given options:
1. [tex]\( \frac{75}{4} ; 18.8 ft \)[/tex]
2. [tex]\( \sqrt{75} ; 9 ft \)[/tex]
3. [tex]\( \frac{\sqrt{75}}{2} ; 4.33 ft \)[/tex]
4. [tex]\( 5 \sqrt{3} ; 8.7 ft \)[/tex]
The correct pair that matches our findings is:
[tex]\[ 5 \sqrt{3} ; 8.7 ft \][/tex]
### Conclusion
Therefore, the correct answer to the problem is:
[tex]\[ 5 \sqrt{3} ; 8.7 ft \][/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.