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Determine if the following chemical equation is balanced:

[tex]\[ Z_n + AgNO_3 \rightarrow 2 On \left( NO_3 \right)_2 + Ag \][/tex]

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GinnyAnsweridn
To balance the given chemical reaction:

[tex]\[ Z_n + AgNO_3 \rightarrow Zn\left(NO_3\right)_2 + Ag \][/tex]

### Step-by-Step Balancing:

1. Write the unbalanced equation:

[tex]\[ Z_n + AgNO_3 \rightarrow Zn\left(NO_3\right)_2 + Ag \][/tex]

2. Identify the number of atoms of each element on both sides of the equation:

- Reactants:
- [tex]\( Zn \)[/tex]: 1
- [tex]\( Ag \)[/tex]: 1
- [tex]\( N \)[/tex]: 1
- [tex]\( O \)[/tex]: 3

- Products:
- [tex]\( Zn \)[/tex]: 1
- [tex]\( Ag \)[/tex]: 1
- [tex]\( N \)[/tex]: 2
- [tex]\( O \)[/tex]: 6

3. Balance the atoms one element at a time:

- Balance the nitrogen (N) and oxygen (O) atoms by adjusting the coefficient of [tex]\(AgNO_3\)[/tex] on the reactant side.

Since there are 2 nitrogen atoms (N) in the product [tex]\( Zn\left(NO_3\right)_2 \)[/tex], you will need 2 molecules of [tex]\( AgNO_3 \)[/tex]:

[tex]\[ Z_n + 2AgNO_3 \rightarrow Zn\left(NO_3\right)_2 + Ag \][/tex]

4. Update the atom count:

- Reactants:
- [tex]\( Zn \)[/tex]: 1
- [tex]\( Ag \)[/tex]: 2
- [tex]\( N \)[/tex]: 2
- [tex]\( O \)[/tex]: 6

- Products:
- [tex]\( Zn \)[/tex]: 1
- [tex]\( Ag \)[/tex]: 1
- [tex]\( N \)[/tex]: 2
- [tex]\( O \)[/tex]: 6

5. Balance the silver (Ag) atoms:

There are 2 silver (Ag) atoms on the reactant side (from [tex]\( 2AgNO_3\)[/tex]), so you need 2 silver atoms on the product side:

[tex]\[ Z_n + 2AgNO_3 \rightarrow Zn\left(NO_3\right)_2 + 2Ag \][/tex]

6. Update and verify the final atom count:

- Reactants:
- [tex]\( Zn \)[/tex]: 1
- [tex]\( Ag \)[/tex]: 2
- [tex]\( N \)[/tex]: 2
- [tex]\( O \)[/tex]: 6

- Products:
- [tex]\( Zn \)[/tex]: 1
- [tex]\( Ag \)[/tex]: 2
- [tex]\( N \)[/tex]: 2
- [tex]\( O \)[/tex]: 6

The equation is now balanced.

### Final Balanced Equation:

[tex]\[ Zn + 2AgNO_3 \rightarrow Zn\left(NO_3\right)_2 + 2Ag \][/tex]

This is the balanced chemical equation for the given reactants and products.
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