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Raul's family is buying a home on an odd-shaped lot. The lengths of three of the sides are given by the expressions shown. The remaining two side lengths are equal to each other. The perimeter of the lot is given by the expression [tex]\(13y + 5\)[/tex].

Which expression gives the length of each remaining side?

A. [tex]\(4y + 8\)[/tex]
B. [tex]\(2y + 4\)[/tex]
C. [tex]\(2y - 1\)[/tex]
D. [tex]\(4y - 2\)[/tex]


Sagot :

Certainly! Let's go through this step by step to find the length of each remaining side.

First, let's use the information given in the problem:

1. We know the perimeter of the lot is given by the expression [tex]\( 13y + 5 \)[/tex].
2. The lengths of three sides are given by the expressions: [tex]\( 4y + 8 \)[/tex], [tex]\( 2y + 4 \)[/tex], and [tex]\( 2y - 1 \)[/tex].
3. The remaining two sides are of equal length, let's denote each of these side lengths as [tex]\( a \)[/tex].

Since the perimeter is the sum of all side lengths, we can set up the following equation:

[tex]\[ 13y + 5 = (4y + 8) + (2y + 4) + (2y - 1) + a + a \][/tex]

Let's simplify this equation step by step:

1. Combine the known side lengths:
[tex]\[ (4y + 8) + (2y + 4) + (2y - 1) = 4y + 8 + 2y + 4 + 2y - 1 \][/tex]

2. Combine like terms on the right side:
[tex]\[ 4y + 2y + 2y + 8 + 4 - 1 = 8y + 11 \][/tex]

The equation now looks like this:
[tex]\[ 13y + 5 = 8y + 11 + 2a \][/tex]

3. To isolate [tex]\( 2a \)[/tex], we'll subtract [tex]\( 8y + 11 \)[/tex] from both sides:
[tex]\[ 13y + 5 - 8y - 11 = 2a \][/tex]

4. Simplify the left side:
[tex]\[ 5y - 6 = 2a \][/tex]

5. Now, to find [tex]\( a \)[/tex], divide both sides by 2:
[tex]\[ a = \frac{5y - 6}{2} \][/tex]

So, the expression that gives the length of each remaining side is:
[tex]\[ \boxed{\frac{5y - 6}{2}} \][/tex]

For example, if [tex]\( y = 2 \)[/tex], the lengths of all sides would be:
- Perimeter expression: [tex]\( 13y + 5 = 31 \)[/tex]
- Side 1: [tex]\( 4y + 8 = 16 \)[/tex]
- Side 2: [tex]\( 2y + 4 = 8 \)[/tex]
- Side 3: [tex]\( 2y - 1 = 3 \)[/tex]
- Each of the remaining two sides: [tex]\( \frac{5y - 6}{2} = 2.0 \)[/tex]

Hence, the lengths of the remaining sides when [tex]\( y = 2 \)[/tex] are 2.0, confirming the calculation:
[tex]\[ \boxed{\frac{5y - 6}{2}} \][/tex] as the correct expression for each remaining side.