Get detailed and reliable answers to your questions with IDNLearn.com. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.

Investments increase exponentially by about [tex]60\%[/tex] every 6 years. If you start with a [tex]\$2500[/tex] investment, how much money would you have after 18 years?

Future Amount = [tex]I(1 + r)^t[/tex]

Calculate the future amount.


Sagot :

Sure! Let's solve this problem step-by-step.

### Step 1: Understanding the Parameters
- Initial Investment (I): [tex]$2500 - Rate of Increase (r): 60% or 0.60 - Total Time (t_years): 18 years - Period (t_period): 6 years ### Step 2: Number of Periods First, we need to determine how many 6-year periods fit into 18 years. \[ \text{Number of periods} = \frac{\text{Total Time (t_years)}}{\text{Period (t_period)}} \] Plugging in the values: \[ \text{Number of periods} = \frac{18 \ \text{years}}{6 \ \text{years/period}} = 3 \] ### Step 3: Future Amount Calculation Next, we will use the formula for exponential increase: \[ \text{Future Amount} = \text{Initial Investment} \times (1 + \text{Rate of Increase})^{\text{Number of Periods}} \] Substitute the given values: \[ \text{Future Amount} = 2500 \times (1 + 0.60)^3 \] ### Step 4: Solving the Equation Now, calculate the factor of the exponential increase: \[ \text{Future Amount} = 2500 \times (1.60)^3 \] ### Step 5: Final Calculation Performing the multiplication: \[ \text{Future Amount} = 2500 \times 4.096 = 10240 \] Therefore, after 18 years, your investment would grow to approximately $[/tex]10,240.00.