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Write an equation for a function that has the shape of [tex]y=x^2[/tex], but is reflected across the [tex]x[/tex]-axis, shifted right 3 units, and up 6 units.

Sagot :

Certainly! Let's address the transformation of the given function [tex]\( y = x^2 \)[/tex]:

1. Reflected across the x-axis:
To reflect [tex]\( y = x^2 \)[/tex] across the x-axis, we multiply the function by [tex]\(-1\)[/tex]. Therefore, the reflection of [tex]\( y = x^2 \)[/tex] across the x-axis is:
[tex]\[ y = -x^2 \][/tex]

2. Shifted right 3 units:
To shift any function [tex]\( y = f(x) \)[/tex] to the right by 3 units, we replace [tex]\( x \)[/tex] with [tex]\( x - 3 \)[/tex] in the function. Let’s apply this to our reflected function [tex]\( y = -x^2 \)[/tex]:
[tex]\[ y = -(x - 3)^2 \][/tex]

3. Shifted up 6 units:
To shift any function [tex]\( y = f(x) \)[/tex] up by 6 units, we add 6 to the function. Applying this to the function [tex]\( y = -(x - 3)^2 \)[/tex]:
[tex]\[ y = -(x - 3)^2 + 6 \][/tex]

Therefore, the equation for the function that has the graph with the shape of [tex]\( y = x^2 \)[/tex], but reflected across the x-axis, shifted right by 3 units, and shifted up by 6 units is:

[tex]\[ y = -(x - 3)^2 + 6 \][/tex]