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Sagot :
To determine if the given nuclear equation is balanced, we need to check both the mass numbers and atomic numbers on each side of the equation.
The equation is:
[tex]\[ \frac{226}{88} Ra \rightarrow \frac{222}{86} Rn + \frac{4}{2} He \][/tex]
1. Check the mass numbers:
[tex]\[ \text{Mass number on the left side} = 226 \][/tex]
[tex]\[ \text{Mass number on the right side} = 222 + 4 = 226 \][/tex]
The mass numbers on both sides are equal (226 = 226).
2. Check the atomic numbers:
[tex]\[ \text{Atomic number on the left side} = 88 \][/tex]
[tex]\[ \text{Atomic number on the right side} = 86 + 2 = 88 \][/tex]
The atomic numbers on both sides are equal (88 = 88).
Since both the mass numbers and atomic numbers are balanced on both sides of the equation, the nuclear equation is balanced.
So, the answer to the question is:
Yes
The equation is:
[tex]\[ \frac{226}{88} Ra \rightarrow \frac{222}{86} Rn + \frac{4}{2} He \][/tex]
1. Check the mass numbers:
[tex]\[ \text{Mass number on the left side} = 226 \][/tex]
[tex]\[ \text{Mass number on the right side} = 222 + 4 = 226 \][/tex]
The mass numbers on both sides are equal (226 = 226).
2. Check the atomic numbers:
[tex]\[ \text{Atomic number on the left side} = 88 \][/tex]
[tex]\[ \text{Atomic number on the right side} = 86 + 2 = 88 \][/tex]
The atomic numbers on both sides are equal (88 = 88).
Since both the mass numbers and atomic numbers are balanced on both sides of the equation, the nuclear equation is balanced.
So, the answer to the question is:
Yes
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