Answered

Find solutions to your problems with the expert advice available on IDNLearn.com. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.

The reaction between calcium carbonate [tex]$\left( CaCO_3 \right)$[/tex] and hydrochloric acid [tex]$(HCl)$[/tex] is represented by the balanced chemical equation below:

[tex]\[ CaCO_3(s) + 2HCl(aq) \rightarrow CaCl_2(aq) + CO_2(g) + H_2O(\ell) \][/tex]

50 grams of calcium carbonate reacts completely to form 0.5 moles of carbon dioxide [tex]$\left( CO_2 \right)$[/tex] at STP.

6.1 Determine the:
6.1.1 Molar mass of calcium carbonate

Sagot :

GinnyAnsweridn
Sure, let's determine the molar mass of calcium carbonate [tex]\((CaCO_3)\)[/tex].

To solve for the molar mass, we need to sum up the atomic masses of all the atoms in the compound:

1. Identify the atomic masses:
- Calcium (Ca): 40.08 g/mol
- Carbon (C): 12.01 g/mol
- Oxygen (O): 16.00 g/mol

2. Count the number of each type of atom in the formula [tex]\(CaCO_3\)[/tex]:
- There is 1 atom of Calcium (Ca).
- There is 1 atom of Carbon (C).
- There are 3 atoms of Oxygen (O).

3. Multiply the atomic masses by the number of each type of atom in the compound and sum them up:
- Contribution from Calcium: [tex]\(1 \times 40.08 = 40.08\)[/tex] g/mol
- Contribution from Carbon: [tex]\(1 \times 12.01 = 12.01\)[/tex] g/mol
- Contribution from Oxygen: [tex]\(3 \times 16.00 = 48.00\)[/tex] g/mol

4. Add these contributions together to get the molar mass of [tex]\(CaCO_3\)[/tex]:
[tex]\[ 40.08 \text{ g/mol (from Ca)} + 12.01 \text{ g/mol (from C)} + 48.00 \text{ g/mol (from O)} = 100.09 \text{ g/mol} \][/tex]

Thus, the molar mass of calcium carbonate [tex]\((CaCO_3)\)[/tex] is 100.09 g/mol.
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.