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An isosceles triangle has two sides of equal length, [tex]a[/tex], and a base, [tex]b[/tex]. The perimeter of the triangle is 15.7 inches, so the equation to solve is [tex]2a + b = 15.7[/tex].

Given that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side, which lengths make sense for possible values of [tex]b[/tex]? Select two options.


Sagot :

To determine the possible values for [tex]\( b \)[/tex], we need to consider both the perimeter constraint and the triangle inequality properties.

Given:
- The two equal sides of the isosceles triangle are each of length [tex]\( a \)[/tex].
- The base of the triangle is [tex]\( b \)[/tex].
- The perimeter of the triangle is 15.7 inches.

So, the perimeter equation is:
[tex]\[ 2a + b = 15.7 \][/tex]

To find possible values of [tex]\( b \)[/tex], we need to solve for [tex]\( a \)[/tex] in terms of [tex]\( b \)[/tex]:
[tex]\[ 2a = 15.7 - b \][/tex]
[tex]\[ a = \frac{15.7 - b}{2} \][/tex]

Next, we need to ensure that the triangle inequality properties are satisfied. The sum of any two sides must be greater than the third side:
1. [tex]\( a + b > a \)[/tex] (automatically satisfied since [tex]\( b \)[/tex] is positive)
2. [tex]\( a + a > b \)[/tex] which simplifies to [tex]\( 2a > b \)[/tex]
3. [tex]\( a + b > a \)[/tex] (same as the first, so automatically satisfied)

Let's focus on the condition [tex]\( 2a > b \)[/tex]:
[tex]\[ 2 \left(\frac{15.7 - b}{2}\right) > b \][/tex]
[tex]\[ 15.7 - b > b \][/tex]
[tex]\[ 15.7 > 2b \][/tex]
[tex]\[ b < 7.85 \][/tex]

So, [tex]\( b \)[/tex] must be less than 7.85 inches. In addition, [tex]\( b \)[/tex] must be a positive value.

Based on the numerical solution, two values of [tex]\( b \)[/tex] that make sense are:
[tex]\[ 0.1 \][/tex]
[tex]\[ 0.11551551551551552 \][/tex]

These values satisfy both the perimeter constraint and the triangle inequality properties.
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