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Nikhil and Mae work at the same company. Nikhil has been at the company 4 times as long as Mae. Nikhil's time at the company is 8 more than 2 times Mae's time. The following system of equations models the scenario:

[tex]
\begin{array}{l}
x = 4y \\
x = 8 + 2y
\end{array}
[/tex]

How many years has each person been employed by the company?

A. Nikhil has been with the company for 16 years, while Mae has been there for 4 years.
B. Nikhil has been with the company for 24 years, while Mae has been there for 6 years.
C. Nikhil has been with the company for 20 years, while Mae has been there for 5 years.
D. Nikhil has been with the company for 12 years, while Mae has been there for 3 years.


Sagot :

To determine how many years Nikhil and Mae have been employed by the company, we'll follow a step-by-step approach to solve the given system of equations:
[tex]\[ \begin{array}{l} x = 4y \\ x = 8 + 2y \end{array} \][/tex]

1. Identify the Equations: We have two equations:
- [tex]\( x = 4y \)[/tex] (Equation 1)
- [tex]\( x = 8 + 2y \)[/tex] (Equation 2)

2. Substitute Equation 1 into Equation 2: Since Equation 1 states [tex]\( x = 4y \)[/tex], we can substitute [tex]\( 4y \)[/tex] for [tex]\( x \)[/tex] in Equation 2:
[tex]\[ 4y = 8 + 2y \][/tex]

3. Solve for [tex]\( y \)[/tex]: Now we will isolate [tex]\( y \)[/tex]:
[tex]\[ 4y - 2y = 8 \][/tex]
Simplify the left side:
[tex]\[ 2y = 8 \][/tex]
Divide both sides by 2:
[tex]\[ y = 4 \][/tex]

4. Determine [tex]\( x \)[/tex] from [tex]\( y \)[/tex]: Now that we have the value of [tex]\( y \)[/tex], substitute it back into Equation 1 to find [tex]\( x \)[/tex]:
[tex]\[ x = 4y \][/tex]
Substitute [tex]\( y = 4 \)[/tex]:
[tex]\[ x = 4 \times 4 = 16 \][/tex]

5. Conclusion:
- Mae has been employed for [tex]\( y = 4 \)[/tex] years.
- Nikhil has been employed for [tex]\( x = 16 \)[/tex] years.

Therefore, the correct answer is:
Nikhil has been with the company for 16 years, while Mae has been there for 4 years.